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Kruka [31]
3 years ago
7

Which of the following is a correct inference that one can make about the burning of gasoline?

Chemistry
1 answer:
VLD [36.1K]3 years ago
4 0

Answer:

It’s a physical change

Explanation:

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How many liters of hydrogen gas are formed from the complete reaction of 1.04 mol of C? Assume that the hydrogen gas is collecte
Alisiya [41]

The volume is 2.23 liters of hydrogen gas.

<u>Explanation</u>:

                  moles of C = grams / molecular mass of C

                                     = 1.04 g / 12.011 g/mol.

                                     = 0.086

        The ratio between C and H2 is 1 : 1

                 moles H2 = 0.086

                               V = nRT / p

                                  = 0.086 x 0.08206 x 316 K / 1.0 atm

                              V  = 2.23 L.

8 0
3 years ago
In a 63.17 g sample of SO3, how many grams are sulfur?
Evgesh-ka [11]

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

0.7890 moles

Mass of sulphar = no of moles× molar mass of sulphar

Mass of sulphur = 0.7890×32.065

25.30 gram

4 0
3 years ago
A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th
tatyana61 [14]

Answer : The partial pressure of the CO_2 in the tank in psia is, 32.6 psia.

Explanation :

As we are given 75 % CO_2 and 25 % N_2 in terms of volume.

First we have to calculate the moles of CO_2 and N_2.

\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole

\text{Moles of }N_2=\frac{\text{Volume of }N_2}{\text{Volume at STP}}=\frac{25}{22.4}=1.12mole

Now we have to calculate the mole fraction of CO_2.

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}

\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75

Now we have to calculate the partial pressure of the CO_2 gas.

\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}

\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the CO_2 in the tank in psia is, 32.6 psia.

3 0
3 years ago
Why is scientific notation useful?
BlackZzzverrR [31]
It condenses very long strings of numbers while retaining the general accuracy of the figure.
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3 years ago
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I think the answer is a
5 0
3 years ago
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