The correct answer is (c) It would have lower ionization energies than K and a lower electronegativity value than K
Explanation- The unknown element belongs to the alkali metals of periodic table. The alkali metal atoms have the largest size in a particular period of the period of periodic table. With the increase in the atomic number, the atom becomes larger.
Atomic radius decreases --> ionization energy increase---->Electronegativity increases. We can use this flow chart to compare the IE and EN of the element. As K have lower radii than the unknown element, so the IE and EN of K will be greater than the unknown element.
Answer:
Elasticity or Flexibility
Explanation:
The ability of an object to resume its normal shape after being stretched or compressed is called elasticity
Ionic bond
Na+ has a POSITIVE charge
while Cl- has a NEGATIVE one.
Through ionic bond both form NACL (Salt).
The answer to the selected question is Flurione
They give a double displacement reaction where the ions switch places and give sodium nitrate (NaNO3) and silver chloride (AgCl) as the products. Silver nitrate is also very soluble in water, but silver chloride is highly insoluble in water and will precipitate out of solution as a white solid.
