The volume is 2.23 liters of hydrogen gas.
<u>Explanation</u>:
moles of C = grams / molecular mass of C
= 1.04 g / 12.011 g/mol.
= 0.086
The ratio between C and H2 is 1 : 1
moles H2 = 0.086
V = nRT / p
= 0.086 x 0.08206 x 316 K / 1.0 atm
V = 2.23 L.
Answer:
25.30 gram
Explanation:
No of moles = given mass / molar mass
No of moles = 63.17/80.06
0.7890 moles
Mass of sulphar = no of moles× molar mass of sulphar
Mass of sulphur = 0.7890×32.065
25.30 gram
Answer : The partial pressure of the
in the tank in psia is, 32.6 psia.
Explanation :
As we are given 75 %
and 25 %
in terms of volume.
First we have to calculate the moles of
and
.


Now we have to calculate the mole fraction of
.


Now we have to calculate the partial pressure of the
gas.


conversion used : (1 Kpa = 0.145 psia)
Therefore, the partial pressure of the
in the tank in psia is, 32.6 psia.
It condenses very long strings of numbers while retaining the general accuracy of the figure.