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7nadin3 [17]
3 years ago
13

Using the table below, what is the change in enthalpy for the following reaction? 3CO (g) + 2Fe2O3 (s) Imported Asset Fe(s) + 3C

O2 (g)
Chemistry
1 answer:
zhuklara [117]3 years ago
3 0

To solve this problem, we should recall that the change in enthalpy is calculated by subtracting the total enthalpy of the reactants from the total enthalpy of the products:

ΔH = Total H of products – Total H of reactants

You did not insert the table in this problem, therefore I will find other sources to find for the enthalpies of each compound.

ΔHf CO2 (g) = -393.5 kJ/mol

ΔHf CO (g) = -110.5 kJ/mol

ΔHf Fe2O3 (s) = -822.1 kJ/mol

ΔHf Fe(s) = 0.0 kJ/mol

Since the given enthalpies are still in kJ/mol, we have to multiply that with the number of moles in the formula. Therefore solving for ΔH:

ΔH = [<span>3 mol </span><span>( − </span><span>393.5 </span>kJ/mol<span>) + 1 mol (</span>0.0 kJ/mol)<span>] − [</span><span>3 mol </span><span>( − </span><span>110.5 </span>kJ/mol<span>) + </span><span>2 mol </span><span>( − </span><span>822.1 </span>kJ/mol<span>)]</span>

ΔH = <span>795.2 kJ</span>

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600,000

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5 0
3 years ago
What structural feature of lecithin allows it to behave like an emulsifying agent?
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6 0
3 years ago
Which of the following describes how a recycling program directly benefits a community economically? The guarantee of no new lan
torisob [31]

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7 0
3 years ago
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7 0
3 years ago
Read 2 more answers
0.101g of calcium is found in 650g of drinking water. what is the concentration in ppm
lukranit [14]
Mass of solute = 0.101 g of calcium

Mass of solvent = 650 g of water

ppm = mass of solute in mg / mass of solvent in Kg

1 g ----- 1000 mg
0.101 g --- ?

mass of  solute = 0.101 * 1000 = 101 mg

1 kg ----- 1000 g
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mass  of solvent = 650 / 1000 = 0,65 Kg

ppm = 101 / 0,65

= 155.38 ppm

hope this helps!


3 0
3 years ago
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