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7nadin3 [17]
3 years ago
13

Using the table below, what is the change in enthalpy for the following reaction? 3CO (g) + 2Fe2O3 (s) Imported Asset Fe(s) + 3C

O2 (g)
Chemistry
1 answer:
zhuklara [117]3 years ago
3 0

To solve this problem, we should recall that the change in enthalpy is calculated by subtracting the total enthalpy of the reactants from the total enthalpy of the products:

ΔH = Total H of products – Total H of reactants

You did not insert the table in this problem, therefore I will find other sources to find for the enthalpies of each compound.

ΔHf CO2 (g) = -393.5 kJ/mol

ΔHf CO (g) = -110.5 kJ/mol

ΔHf Fe2O3 (s) = -822.1 kJ/mol

ΔHf Fe(s) = 0.0 kJ/mol

Since the given enthalpies are still in kJ/mol, we have to multiply that with the number of moles in the formula. Therefore solving for ΔH:

ΔH = [<span>3 mol </span><span>( − </span><span>393.5 </span>kJ/mol<span>) + 1 mol (</span>0.0 kJ/mol)<span>] − [</span><span>3 mol </span><span>( − </span><span>110.5 </span>kJ/mol<span>) + </span><span>2 mol </span><span>( − </span><span>822.1 </span>kJ/mol<span>)]</span>

ΔH = <span>795.2 kJ</span>

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alexira [117]
<h2>Answer </h2>

Option C - 320J

<u>Explanation </u>

Since ethanol solid at −120 °C and is only cooling down (it won’t change states) . The amount of Thermodynamic properties values c is given in form of solid, liquid and gas. Amount of energy released is calculated below.  

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Plants undergo photosynthesis to produce glucose according to the reaction below. What mass of water is required to produce 5.0g
solniwko [45]

Answer:

option a) 3 g

Explanation:

mass of Glucose = 5 g

Mass of H₂O = ?

Reaction Given:

                   6CO₂ + 6H₂O ----> C₆H₁₂O₆ + 6O₂

Solution:

First we have to find mass of glucose from balanced reaction.

So,

Look at the reaction

                        6CO₂ + 6H₂O -------> C₆H₁₂O₆ + 6O₂

                                     6 mol               1 mol

As 6 mole of water (H₂O) give 1 mole of Glucose (C₆H₁₂O₆ )

Convert moles to mass

molar mass of C₆H₁₂O₆  = 6(12) + 12(1) + 6(16)

molar mass of C₆H₁₂O₆  = 72 + 12 + 96

molar mass of C₆H₁₂O₆= 180 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now

             6CO₂      +  6H₂O          --------->     C₆H₁₂O₆   +    6O₂

                              6 mol (18 g/mol)           1 mol (180 g/mol)

                                  108 g                            180 g

108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆)

So

if 108 g of water (H₂O) produce 180 g of glucose (C₆H₁₂O₆) so how many grams of water (H₂O) will be required to produce 5 g of glucose (C₆H₁₂O₆).

Apply Unity Formula

               108 g of water (H₂O) ≅ 180 g of glucose (C₆H₁₂O₆)

                X g of water (H₂O) ≅ 5 g of glucose (C₆H₁₂O₆)

Do cross multiply

                     mass of water (H₂O) = 108 g x 5 g / 180 g

                     mass of water (H₂O) = 3 g

So 3 g of water is required to produce 5 g of glucose.  

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prohojiy [21]

Answer:

The reaction will move to the left.

Explanation:

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<em>Ba(OH)₂ = Ba²⁺ + 2OH⁻,</em>

<em>Ba(OH)₂ is dissociated to Ba²⁺ and 2OH⁻.</em>

  • If H⁺ ions are added to the equilibrium:

H⁺ will combine with OH⁻ to form water.

<em>So, the concentration of OH⁻ will decrease and the equilibrium is disturbed.</em>

<em />

<em>According to Le Châtelier's principle: </em>when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

  • So, the reaction will move to the right to suppress the effect of decreasing OH⁻ concentration.

  • The base will dissociate to form more OH⁻ and thus, the quantity of Ba(OH)₂ will decrease.

<em>So, the right choice is: the reaction will move to the left, is the choice that will not happen to the equilibrium.</em>

5 0
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