There are 7 periods in the modern periodic table
MM Zn(NO₃)₂ = 189.36 g/mol
mass 1 mol Zn(NO₃)₂ = 189.36 g
mass hydrate = 100 / 63.67 x 189.36 = 297.409 g
mass 1 mol hydrate = 297.409 g
MM hydrate = 297.409 g/mol
MM hydrate = MM Zn(NO₃)₂ + MM xH₂O
297.409 = 189.36 + x(18)
x = 6
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Explanation:
Answer:
The correct answer is 4.16 grams.
Explanation:
Based on the given information, the concentration of KCl solution is 16 % m/v, which means that 100 ml of the solution will contain 16 grams of KCl.
The molarity of the solution can be determined by using the formula,
M = weight/molecular mass × 1000/Volume
The molecular mass of KCl is 74.6 grams per mole.
M = 16/74.6 × 1000/100
M = 16/74.6
M = 2.14 M
Now the weight of KCl present in the solution of 26 ml will be,
2.14 = Wt./74.6 × 1000 /26
Wt. = 4.16 grams
