Which are the followings and where is the data graphed i need a picture in order to help you
Answer:
Explanation:
So , these molecules would want to fill up their shell in order to become stable, which means they would want a total of 8 electrons.
As you can see in the first example, the Carbon has 4 electrons (one dot on each side of the C), however this is not enough as it has not reached 8, so it is unstable. The Carbon would want a full pair of electrons, however it only has a lone electron as there is only one electron per side.
To become stable, it would require 4 more electrons, and as you can see, there are 4 hydrogens, which have one electron each. that means there is a total of 4 hydrogens.
So, the hydrogens and carbon would bond, and the Hydrogen would share one of its electrons to the carbon so it can have a full pair.
Same concept for ammonia
Nitrogen has 5 electrons (meaning it requires 3 more to reach 8) , and 3 of the electrons are lone and need one more to complete the pair. So, the Hydrogen would provide these 3 electrons by joining up with N where there is only one dot on the N.
Hope it makes sense ,
you could search "electron dot diagram for NH3 " to see how it looks
X volume= 2x2x2=8
y volume= 8x8x8=512
512/8=64 so you can fit 64
2 C8H18 + 25 O2 = 16 CO2 + 18 H2<span>O
Above is properly balanced but as you want 1 mole. divide everything by 2
</span>C8H18 + 12.5O2 = 8CO2 + 9H2<span>O</span>
Answer:
8.75 mL
Explanation:
First, we calculate the molar mass of NaCl = molar mass of Na + molar mass of Cl. Molar mass of Na = 23 g/mol, molar mass of Cl = 35.5 g/mol.
So molar mass NaCl = (23 + 35.5) g/mol = 58.5 g/mol. The number of moles ,n of NaCl in 12.5g is n = mass of NaCl/ molar mass NaCl = 12.5 g / 58.5 g/mol = 0.214 mol.
The molarity, M of 150 mL M = number of moles/ volume = 0.214 mol / 150 mL = 1.427 M.
We now calculate the number of moles of NaCl in 250 mL of 0.500 M.
Number of moles, n = molarity × volume. molarity = 0.500 M, volume = 250 mL. So n = 0.500 × 250 = 0.125 moles. Since we have 0.125 moles in the dilute 250 mL solution, the volume of the 150 mL 1.43 M solution required is number of moles in 250 mL solution/molarity of 150 mL solution = 0.125 mol / 1.427 M = 0.0875 L = 8.75 mL