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Brilliant_brown [7]
2 years ago
15

This question looks so simple , but I don’t want to get it won’t could I get help .

Physics
2 answers:
Doss [256]2 years ago
4 0

Answer:

I would think a vector but double check that before turning it in

Explanation:

zalisa [80]2 years ago
4 0
I think it’s vector
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se lanza un cuerpo desde el origen con velocidad horizontal de 40 m/s, y con un ángulo de 60º. calcular la máxima altura y el al
EastWind [94]

Answer:

1. h = 244.8 m    

2. x = 564.8 m  

Explanation:

1. La altura máxima se puede calcular usando la siguiente ecuación:

v_{f}^{2} = v_{0}^{2} - 2gh     (1)                        

Where:

v_{f_{y}}: es la velocidad final = 0 (en la altura máxima)  

v_{0_{y}}: es la velocidad inicial horizontal en "y"

g: es la gravedad = 9.81 m/s²          

h: es la altura máxima =?

La velocidad incial en "y" se puede calcular de la siguiente manera:

tan(\theta) = \frac{v_{0_{y}}}{v_{0_{x}}}

v_{0_{y}} = tan(60)*40 m/s = 69.3 m/s                    

Resolviendo la ecuación (1) para "h" tenemos:

h = \frac{v_{0_{y}}^{2}}{2g} = \frac{(69.3 m/s)^{2}}{2*9.81 m/s^{2}} = 244.8 m          

2. Para calcular el alcance horizontal podemos usar la ecuación:

x = v_{x}*t

Primero debemos encontrar el tiempo cuando la altura es máxima (v_{f_{y}} = 0).

v_{f_{y}} = v_{0_{y}} - gt    

t = \frac{v_{0_{y}}}{g} = \frac{69.3 m/s}{9.81 m/s^{2}} = 7.06 s      

Ahora, como el tiempo de subida es el mismo que el tiempo de bajada, el tiempo máximo es:

t_{m} = 2*7.06 s = 14.12 s          

Finalmente, el alcance horizontal es:

x = 40 m/s*14.12 s = 564.8 m                                                            

Espero que te sea de utilidad!

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3 years ago
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6 0
3 years ago
Ordinary kriging method assume that​
Nata [24]

ears

Explanation:

I want to eat your ears

7 0
3 years ago
Why are some atoms radioactive
Dmitry_Shevchenko [17]
Atoms<span> are made of three types of sub-atomic particle: neutrons and protons in the nucleus and electrons orbiting the nucleus. </span>Some<span> materials are </span>radioactive<span> because the nucleus of each </span>atom<span> is unstable and gives out nuclear radiation in the form of alpha particles, beta particles or gamma rays.</span>
8 0
3 years ago
You stand on a merry-go-round which is spinning at f = 0.25 revolutions per second. You are R = 200 cm from the center. (a) Find
wariber [46]

Answer:

a) ω = 9.86 rad/s

b) ac = 194. 4 m/s²

c) minimum coefficient of static friction, µs = 19.8

Explanation:

a) angular speed, ω = 2πf, where f is frequency of revolution

1 rps = 6.283 rad/s, π = 3.142

ω = 2 * 3.14 * 0.25 * 6.28

ω = 9.86 rad/s

b) centripetal acceleration, a = rω²

where r is radius in meters; r = 200 cm or 2 m

a = 2 * 9.86²

a = 194. 4 m/s²

c) µs = frictional force/ normal force

frictional force = centripetal force = ma; where a is centripetal acceleration

normal force = mg; where g = 9.8 m/s²

µs = ma/mg = a/g

µs = 194.4 ms⁻²/9.8 ms⁻²

c) minimum coefficient of static friction, µs = 19.8

5 0
2 years ago
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