Answer:
a) pH = 4.213
b) % dis = 2 %
Explanation:
Ch3COONa → CH3COO- + Na+
CH3COOH ↔ CH3COO- + H3O+
∴ Ka = 1.8 E-5 = ([ CH3COO- ] * [ H3O+ ]) / [ CH3COOH ]
mass balance:
⇒ <em>C</em> CH3COOH + <em>C</em> CH3COONa = [ CH3COOH ] + [ CH3COO- ]
<em>∴ C </em>CH3COOH = 3.40 mM = 3.4 mmol/mL * ( mol/1000mmol)*(1000mL/L)
∴ <em>C</em> CH3COONa = 1.00 M = 1.00 mol/L = 1.00 mmol/mL
⇒ [ CH3COOH ] = 4.4 - [ CH3COO- ]
charge balance:
⇒ [ H3O+ ] + [ Na+ ] = [ CH3COO- ] + [ OH- ]....is negligible [ OH-], comes from water
⇒ [ CH3COO- ] = [ H3O+ ] + 1.00
⇒ Ka = (( [ H3O+ ] + 1 )* [ H3O+ ]) / ( 3.4 - [ H3O+])) = 1.8 E-5
⇒ [ H3O+ ]² + [ H3O+ ] = 6.12 E-5 - 1.8 E-5 [ H3O+ ]
⇒ [ H3O+ ]² + [ H3O+ ] - 6.12 E-5 = 0
⇒ [ H3O+ ] = 6.12 E-5 M
⇒ pH = - Log [ H3O+ ] = 4.213
b) (% dis)* mol acid = <em>C</em> CH3COOH = 3.4
∴ mol CH3COOH = 500*3.4 = 1700 mmol = 1.7 mol
⇒ % dis = 3.4 / 1.7 = 2 %
Answer:
it is because of the bacteria and different things that go into waters such as ponds, rivers, lakes, seas, oceans, streams, and other body of waters and I should also add the chemicals that go into them as well
Explanation:
Explanation:
Thomson's suggested the plum pudding model of the atom in which the atomic space is made up of electrons surround by positive charges.
Rutherford in his gold foil experiment revised the plum pudding model of the atom;
- He discovered that most of the alpha particles passed through the foil while a few of them were deflected back.
- To explain this observation, he suggested the atomic model of the atom.
- In this model, an atom is made up of a small positively charged center where nearly all the mass is concentrated.
- Surrounding the nucleus is the extranuclear part made up of electrons.
First one is False. The second is true.
Answer:
6.022 x 10^23 particles
Explanation:
Chemists have chosen to count atoms and molecules using a unit called the mole (mol), from the Latin moles, meaning “pile” or “heap.”
One mole is 6.022 x 10^23 of the microscopic particles which make up the substance in question.
Hope this helped! :^)
