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nordsb [41]
3 years ago
15

What is the solubility of salt in water at room temperature

Chemistry
1 answer:
rewona [7]3 years ago
5 0
<h3><u>Answer;</u></h3>

357 mg/mL

<h3><u>Explanation;</u></h3>
  • Solubility is defined to be the maximum amount of solute that will dissolve in a given amount of solvent at a specific temperature. The solubility of a salt is one of many physical properties that depend on temperature.
  • At room temperature 25 °C, the solubility of salt or Sodium Chloride is 357 mg/mL.
  • For many solutes, increasing the temperature increases the solubility of the solute. The solubility of sodium chloride or table salt is only slightly affected by temperature increase.
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Why do plants need sunlight for photosynthesis?
igomit [66]

Explanation: Plants using photosynthesis will take in carbon dioxide from the air, bring up water from the roots, and use sunlight as the energetic source to create sugar from water and carbon dioxide. Plants contain a molecule called chlorophyll, and the chlorophyll is what absorbs the sunlight

7 0
3 years ago
Read 2 more answers
How do you balance the equation in number one?
AleksAgata [21]
____NaNO3 + ___PbO --> ___Pb(NO3)2 + ___Na[2]O

To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side. 

To start off, you wanna know the number of atoms in each element on both sides, so take it apart:

[reactants]        [product]
Na- 1               Na- 2

N- 1               N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)

O- 4              O- 7 (same reason as above) 

Pb- 1            Pb- 1 

Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2: 

2NaNO3

Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become: 

Na- 2             Na- 2 

N- 2              N- 2 (it balanced out) 

O- 7 (coefficient times subscript, plus lone O)  O- 7 (balanced out) 

Pb was already balanced so no need to mess with it, just put a 1 where needed (it doesn't change anything). 

Now to put it back together, it will look like this: 

2NaNO3 + 1PbO --> 1Pb(NO3)2 + 1Na[2]O
3 0
3 years ago
What would be the freezing point of a solution that has a molality of 1.324 m which was prepared by dissolving biphenyl (C12H10)
lbvjy [14]

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

A solution is prepared by dissolving biphenyl into naphthalene. We can calculate the freezing point depression (ΔT) for naphthalene using the following expression.

\Delta T = i \times Kf \times m =   1 \times 6.90 \°C/m  \times 1.324m = 9.14  \°C

where,

  • i: van 't Hoff factor (1 for non-electrolytes)
  • Kf: cryoscopic constant
  • m: molality

The normal freezing point of naphthalene is 80.26 °C. The freezing point of the solution is:

T = 80.26 \° C - 9.14 \° C = 71.12 \° C

The freezing point of a 1.324 m solution, prepared by dissolving biphenyl into naphthalene, is 71.12 ° C.

Learn more: brainly.com/question/2292439

3 0
2 years ago
HELP ME PLEASE
Alika [10]

Answer: it is a good conductor of electriciy tht is what wires are made of and it is a good conductor of heat so it will be able to handle the heat from the electricity

Explanation:

7 0
3 years ago
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How many moles of ba(oh)2 are present in 275 ml of 0.200 m ba(oh)2?
DENIUS [597]
You have to put your attention to the unit of concentration. It is expressed in terms of molarity, which is represented in M. It is the number of moles solute per liter solution. So, you simply have to multiply the molarity with the volume in liters.

Volume = 275 mL * 1 L/1000 mL = 0.275 L
<em>Moles Ba(OH)₂ = (0.200 M)(0.275 L) = 0.055 mol</em>
6 0
3 years ago
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