Answer:
0.077M
Explanation:
Step 1:
The balanced equation for the reaction. This is given below:
2HCl + Mg(OH)2 —> MgCl2 + 2H2O
From the balanced equation above,
The mole ratio of the acid (nA) = 2
The mole ratio of the base (nB) = 1
Step 2:
Data obtained from the question.
Concentration of base Cb =...?
Volume of base (Vb) = 10mL
Concentration of acid (Ca) = 0.1M
Volume of acid (Va) = 15.4mL
Step 3:
Determination of the concentration of the base, Mg(OH)2.
The concentration of the base can be obtained as follow:
CaVa/CbVb = nA/nB
0.1 x 15.4 /Cb x 10 = 2/1
Cross multiply to express in linear form
Cb x 10 x 2 = 0.1 x 15.4
Divide both side by 10 x 2
Cb = (0.1 x 15.4) /(10 x 2)
Cb = 0.077M
Therefore, the concentration of the base, Mg(OH)2 is 0.077M
