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2 years ago

15

I am a gas. I am in the noble gas family and row 1. I have only 2 valence electrons I glow red-orange when in an electric field.

I can also be found in the sun. Who am I?

2 answers:

belka [17]2 years ago

7 0

The element is Helium

Goodluck!

Lubov Fominskaja [6]2 years ago

6 0

Answer:

the elements its helium

Explanation:

ithink its help

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How much heat is released when 105g of steam at 100.0C is cooled to ice at -15C? Enthalpy of vaporization of water is 40.67kj/mo

densk [106]

Answer:

4909.486Kj/mol

Explanation:

the heat would be required to change steam at 100°c to water at 100°c then change the water at that temperature to water at 0°c then change water at 0°c to ice at 0°c then ice at 0°c to ice at -15°c

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3 years ago

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The average kinetic energy of the atoms that make up a substance which is changing from a liquid to a solid is _____________.dec

Zepler [3.9K]

Here is your answer:

Your answer is A decreasing.

Reason: That's because when your turning into a solid your not moving and kinetic energy is the around of movement an object is moving.

Your answer is A.

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3 years ago

What is the number of moles of ammonia gas formed when 0.5 mole of nitrogen gas is reacted with excess of hydrogen gas?

Troyanec [42]

Answer: 1.5mol NH3

Explanation: 1N2+3H2= NH3

0.5 mol N2x 3NH3/1molN2= 0.5x3= 1.5mol NH3

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1 year ago

Dahasolnce [82]

Answer:

reproduction

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2 years ago

If the freezing point of the solution had been incorrectly read 0.3 °C lower than the true freezing point, would the calculated

Dovator [93]

Answer : The molar mass of the solute would be low.

Explanation :

Formula used for depression in freezing point is:

$\Delta T_f=i\times K_f\times m\\\\T^o-T_s=i\times K_f\times\frac{w_b}{M_b}\times w_a}$

where,

$\Delta T_f$ = change in freezing point

$\Delta T_s$ = freezing point of solution

$\Delta T^o$ = freezing point of water

i = Van't Hoff factor

$K_f$ = freezing point constant

m = molality

$w_b$ = mass of solute

$w_a$ = mass of solvent

$M_b$ = molar mass of solute

From the formula we conclude that, when the freezing point of the solution read incorrectly that is freezing point of the solution is lower than the true freezing point then this means that change in freezing point would be high and the molar mass of the solute would be low.

Hence, the molar mass of the solute would be low.

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3 years ago