Answer:
83.99 KC1 1.
Explanation:
What is the total number of grams of KCl (formula 2.200M=xmol - 200 mdr o mass = 74.6) in 1.00 liter of 0.200 molar solution? 3941+355 74.69 ml atonal 1.13 mol 174.6g) = 83.99 KC1 1.
They have the same amount of valence electrons
Answer:
Mass = 14.876 g
Explanation:
Given data:
Volume of gold = 0.77 cm³
Mass of gold = ?
Solution:
Density of gold from literature is 19.32 g/cm³
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
19.32 g/cm³ = m/ 0.77 cm³
m = 19.32 g/cm³ × 0.77 cm³
m = 14.876 g
Answer:
Q14: 17,140 g = 17.14 kg.
Q16: 504 J.
Explanation:
<u><em>Q14:</em></u>
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat absorbed by ice (Q = 3600 x 10³ J).
m is the mass of the ice (m = ??? g).
c is the specific heat of the ice (c of ice = 2.1 J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 100.0°C - 0.0°C = 100.0°C).
∵ Q = m.c.ΔT
∴ (3600 x 10³ J) = m.(2.1 J/g.°C).(100.0°C)
∴ m = (3600 x 10³ J)/(2.1 J/g.°C).(100.0°C) = 17,140 g = 17.14 kg.
<u><em>Q16:</em></u>
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat absorbed by ice (Q = ??? J).
m is the mass of the ice (m = 12.0 g).
c is the specific heat of the ice (c of ice = 2.1 J/g.°C).
ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 0.0°C - (-20.0°C) = 20.0°C).
∴ Q = m.c.ΔT = (12.0 g)(2.1 J/g.°C)(20.0°C) = 504 J.
