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3 years ago

Litmus paper can be used to determine the _______ of a substance.

Chemistry

1 answer:

givi [52]3 years ago

6 0

Answer: relative ph

Explanation:

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Explain why oil is called a fossil fuel.

Dmitrij [34]

Oil is referred to as a fossil fuel because it is derived from fossils.

Fossil fuels are the result of dinosaur remains being put under pressure for millions of years.

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3 years ago

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An analytical chemist weighs out 0.188 g of an unknown triprotic acid into a 250 mL volumetric flask and dilutes to the mark wit

Anon25 [30]

Answer: The molar mass of unknown triprotic acid is 97.66 g/mol

Explanation:

To calculate the molarity of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of triprotic acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.0600M\\V_2=95.9mL$

Putting values in above equation, we get:

$3\times M_1\times 250=1\times 0.0600\times 95.9\\\\M_1=0.0077M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.0077 M

Given mass of triprotic acid = 0.188 g

Volume of solution = 250 mL

Putting values in above equation, we get:

$0.0077M=\frac{0.188\times 1000}{\text{Molar mass of triprotic acid}\times 250}\\\\\text{Molar mass of triprotic acid}=97.66g/mol$

Hence, the molar mass of unknown triprotic acid is 97.66 g/mol

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3 years ago

X) = 3x - 13 g(x) = 2x2 - 4x-5 {x) = -4-7 6. Find (f- g(x).

Nastasia [14]

Answer:

sorry

Explanation:

don know

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3 years ago

How many moles of Pb(NO3)2 are required

yarga [219]

Answer:

12 moles Pb(NO₄)₂ needed.

Explanation:

3Pb(NO₃)₂ +2AlCl₃ => 3PbCl₂ + 2Al(NO₃)₃

Given => ? moles 8 moles

from reaction stoichiometry, 2 moles AlCl₃ requires 3 moles Pb(NO₄)₂ then 8 moles AlCl₃ requires 3/2(8) moles of the Pb(NO₄)₂ => 12 moles Pb(NO₄)₂ needed.

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3 years ago

If you dilute 250 mL of 6.4 M lithium acetate solution to a volume of 750 mL, what will the concentration of this solution be?

Tresset [83]

The answer would be 1006.4

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3 years ago