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liraira [26]
3 years ago
12

Litmus paper can be used to determine the _______ of a substance.

Chemistry
1 answer:
givi [52]3 years ago
6 0

Answer: relative ph

Explanation:

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The Ostwald process is used commercially to produce nitric acid, which is, in turn, used in many modern chemical processes. In t
const2013 [10]

Answer:

\boxed{\text{47.4 g}}

Explanation:

We are given the mass of two reactants, so this is a limiting reactant problem.

We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:    17.03   32.00                 18.02  

           4NH₃ + 5O₂ ⟶ 4NO + 6H₂O

m/g:     70.1      70.1

Step 1. Calculate the moles of each reactant

\text{Moles of CO } = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{17.03 g}} = \text{4.116 mol}\\\\\text{Moles of H$_{2}$O} = \text{70.1 g} \times \dfrac{\text{1 mol}}{\text{32.00 g}} = \text{2.191 mol}

Step 2. Identify the limiting reactant  

Calculate the moles of H₂O we can obtain from each reactant.

From NH₃:

The molar ratio of H₂O:NH₃ is 6:4.

\text{Moles of H$_{2}$O} = \text{4.116 mol NH$_{3}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{4 mol NH$_{3}$}} = \text{6.174 mol H$_{2}$O}

From O₂:  

The molar ratio of H₂O:O₂ is 6:5.  

\text{Moles of H$_{2}$O} = \text{2.191 mol O$_{2}$} \times \dfrac{\text{6 mol H$_{2}$O}}{\text{5 mol O$_{2}$}} = \text{2.629 mol H$_{2}$O}

O₂ is the limiting reactant because it gives the smaller amount of H₂O.  

Step 3. Calculate the theoretical yield.

\text{Theor. yield } = \text{2.629 mol H$_{2}$O}\times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{47.4 g H$_{2}$O}\\\\\text{The maximum yield of H$_{2}$O is }\boxed{\textbf{47.4 g}}

6 0
3 years ago
What are the advantages of using a computer over a graphing calculator
andrezito [222]
The answer to this question is:

The advantages of using a computer over a graphing calculator is the the "Computer larger amount of data" then the graphing calculator 

Hope this helped, Laffertytyler20
Your Welcome :)
5 0
3 years ago
Here is the reaction of carbamic acid and ammonia to form an amide and water. There is a scheme of a reversible reaction where c
vladimir2022 [97]

Answer:

See explanation

Explanation:

I have attempted to show the sequence of the reaction between carbamic acid and ammonia to form an amide and water and urea.

The reaction first involves the protonation of ammonia to give ammonium carbamate.

When ammonium carbamate is heated to 130-140 degrees, we obtain urea and water as the final products of the reaction

4 0
2 years ago
What is the volume of the rectangular prism below? A.38,832 mm3 B.480,000 mm3 C.499,200 mm3 D.501,120 mm3
Mkey [24]

Answer:

c.

Explanation:

8 0
3 years ago
In sexual reproduction, if each chromosome in a pair has the same genes, how is genetic variety possible?
ruslelena [56]

Answer:

The same genes or slightly different versions of the same gene can be found on each chromosome in a pair. They form a line and split off bits of themselves, which they barter with one another. In sexual reproduction, crossing over is the first method that genes are shuffled to develop genetic variation.

4 0
2 years ago
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