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Juli2301 [7.4K]
3 years ago
10

What would be the mass of a 33.5dm3 sample of O2 at STP?

Chemistry
1 answer:
liraira [26]3 years ago
7 0

Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

{ \tt{22.4 \:  {dm}^{3}   \: \dashrightarrow \: 16 \: grams}} \\  { \tt{33.5 \:  {dm}^{3}  \:  \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\  \\  \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}

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Answer:

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Explanation:

(Step 1)

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(Step 2)

Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.

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(Step 3)

Calculate the molarity of LiOH using the molarity equation.

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