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Juli2301 [7.4K]
2 years ago
10

What would be the mass of a 33.5dm3 sample of O2 at STP?

Chemistry
1 answer:
liraira [26]2 years ago
7 0

Answer:

• One mole of oxygen is equivalent to 16 grams.

→ But at STP, 22.4 dm³ are occupied by 1 mole.

{ \tt{22.4 \:  {dm}^{3}   \: \dashrightarrow \: 16 \: grams}} \\  { \tt{33.5 \:  {dm}^{3}  \:  \dashrightarrow \: ( \frac{33.5 \times 16}{22.4} ) \: grams}} \\  \\  \dashrightarrow \: { \boxed{ \tt{23.94 \: g \approx \: 24 \: grams}}}

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Can someone tell me how to do this steps by step<br>How many grams is there in 3.65 moles of CuSO4
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1. you need a periodic table and find the atomic mass of Cu (copper), S (sulfur) and O (oxygen). The atomic mass is the number in the box that corresponds to the element and have several decimal places.

2. atomic mass of 
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3. Then according to the formula of the compound, you add as many time the atomic mass of each element as subindex in the formula and add all the values together to calculate the molecular mass of the compound in grams.

4. 63.546 g + 32.065 g + ( 4 x <span>15.9994) = 159.609 g

5.  this value </span><span>159.609 g is the mass in grams of one mol of CuSO4

6 the problem is asking not for the mass of one mole but the mass of 3.65 moles of CuSO4

7 then you have the multiply the value of one mol by the number of moles that the problem is asking you

8. </span><span>159.609 g x 3.65 = 582.571 g
</span>
9 the answer to the problem will be
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6 0
2 years ago
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