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Aleksandr-060686 [28]

3 years ago

14

Como se chama o processo de de transformação da larva do indivíduo adulto? Dê exemplos de animais que passam por esse processo.

1 answer:

Ugo [173]3 years ago

6 0

Answer:

o processo e de metamorfose. As borboletas e outrostipos de insetos.....

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Compare the density of the ocean crust and the continental crust. If they were to collide, predict which one would push under th

uysha [10]

Answer:

The difference between the density of the ocean crust and the continental crust is the fact that the ocean crust is denser than the continental crust. Meaning, the continental crust is likely to push over the oceanic crust considering it has less dense.

Explanation:

I hope this helps, the last time I learned this was in 5th grade and I am i currently in the 11th grade....

5 0

3 years ago

What is the chemical formula of (Sodium hydroxide ) ??

Margaret [11]

$\huge{ \color{black}{ \boxed{ \color{hotpink}{Answer}}}}$

what is the chemical formula of (Sodium hydroxide ) ??

<h3> ⚘ NaOH</h3>

Sodium hydroxide, Sodium oxidanide

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$\large\tt\:⚘ \: MishiChaeYoon \: ⚘$

4 0

3 years ago

Which electromagnet would have the most strength?

ycow [4]

The one with 20 coils as it can generate more electricity.

8 0

3 years ago

Read 2 more answers

Al2O3 would be typed in as Al2O3 Al2(SO4)3 would be typed in as Al2(SO4)3.

N76 [4]

Answer:

Explanation:

Hello,

We are required to write the chemical formula of the following compounds

1. Calcium nitride = Ca₃N₂

2. Magnesium Phosphide = Mg₃P₂

3. Rubidium Chromate = Rb₂CrO₄

4. Aluminium nitrate = Al(NO₃)₃

5. Ammonium Arsenide = (NH₄)₃As

6. Nickel(ii) nitrite = Ni(NO₂)₂

7. Copper(i)sulfate = Cu₂SO₄

8. Iron(iii)nitrate = Fe(NO₃)₃

9. Manganese(ii)nitrate = Mn(NO₃)₂

The left hand side are the common names when the right hand side are the chemical formula.

4 0

4 years ago

The PH of a 0.1 M MCl (M is an unknown cation) was found to be 4.7. Write the net ionic equation for the hydrolysis of M and its

Serggg [28]

Answer:

6.25 X10^{-9} = Ka

$Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}$

Explanation:

The ionic equation for the hydrolysis of the cation of the given salt will be:

$M^{+} + H_{2}O ---> MOH + H^{+}$

The expression for Ka will be:

Ka = $\frac{[H^{+}][MOH]}{[M^{+}]}$

As given that the concentration of the salt is 0.1 M and pH of solution = 4.7, we can determine the concentration of Hydrogen ions from the pH

pH = -log [H⁺]

[H⁺] = antilog(-pH) = antilog (-4.7) = 2 X 10⁻⁵ M = [MOH]

Let us calculate Ka from this,

Ka = ${2.5X10^{-5}X2.5X10^{-5}}{0.1} = 6.25 X10^{-9}$

The relation between Ka an Kb is

KaXKb =10⁻¹⁴

$Kb= \frac{10^{-14}}{6.25 X10^{-9}}= 1.6X10^{-6}$

6 0

3 years ago