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tester [92]
3 years ago
12

What is the number of moles of chemical units represented by 9.03x10^24? And how do I show work? (DUMB IT DOWN PLEASE)

Chemistry
1 answer:
Goryan [66]3 years ago
6 0
You have to use avagados number... so toy take your starting number and multiple by 1/avagados number which is like 6.002^23 and that will equal your number of males... avagado always associates with moles... look up that exact number though bc I cant remember it
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The reduction of 3-pentanone with hydrogen in the presence of a nickel catalyst will yield The reduction of 3-pentanone with hyd
Zinaida [17]

Answer:

d. diethyl alcohol

Explanation:

When ketones undergo reduction, they produce 2° alcohol, and 3-pentanone will produce dimethl alcohol as the secondary (2°) alcohol

5 0
3 years ago
What is the mass in grams of KBr in 0.400 L of a 0.350 M solution???
melamori03 [73]

Answer:

The answer to your question is: 16.7 g of KBr

Explanation:

Data

mass KBr = ? g

Volume = 0.400 L

Concentration = 0.350 M

Formula

Molarity = moles / volume

moles = molarity x volume

Process

moles = (0.350)(0.400)

          = 0.14

MW KBr = 39 + 80 = 119 g

                                  119 g of KBr --------------------  1 mol

                                   x                 --------------------   0.14 mol

                                   x = (0.14 x 119) / 1

                                   x = 16.7 g of KBr

8 0
3 years ago
Read 2 more answers
Please help me i’m struggling
Marrrta [24]

Answeeeeer:

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3 0
3 years ago
erchlorates are powerful oxidizing agents used in fireworks, flares, and space shuttle booster rockets. Lewis structures for the
Bess [88]

Answer:

1.75

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

7 0
3 years ago
8. Given the balanced chemical equation Br2 + 2 NaI -> 2 NaBr + I2 How many moles of sodium bromide (NaBr) could be produced
bezimeni [28]

Since we are already given the balanced equation:


Br_{2}+2NaI → NaBr+I_{2}


We can derive the molar ratios as: 1:2:1:1


That being said, we are given 0.172 moles of bromine (Br_{2}), so it has a ratio of 1:1 with sodium bromide (NaBr).


So we can take from that ratio, that when 0.172 moles of bromine are used, we are, in turn, going to get 0.172 moles of sodium bromide produced.

4 0
4 years ago
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