Alright sure:
Q5: ∠3
Q6: ∠1
Q7: ∠2
Q8: x = 25
Q9: x = 63
For Questions 8 and 9 what I did was find out the supplementary angle adjacent to the exterior angle.
8: 180° in a supp. angle. So 180-105 = 75. To make a triangle it has to be 180°. So 180 - 75-80 = 25 So x=25
9: 180° in a supp. angle. So 180-135 = 45. To make a triangle it has to be 180°. So 180 - 45-72 = 63. So x=63
Let me know if you don't understand that. If you don't get it I'll explain it further for you.
Answer:
•all angles must be equal/congruent.
•all sides must be the same length
•all vertices must be the same distance from the midpoint of the side across from it
Step-by-step explanation:
please stay safe during corona virus. i know you wanna leave and hang out with your friends but please respect social distancing. please have a good day.
Answer:
n' = (-5,2) k' = (-1,1) t' = (-5,0)
Step-by-step explanation:
Answer:
a=6 and b=7
Step-by-step explanation:
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Answer:
![f^{-1}(x)=\dfrac{\sqrt[3]{x}+1}{2}}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7Bx%7D%2B1%7D%7B2%7D%7D)
Step-by-step explanation:
Interchange x and y in the function definition and solve for y.
![x=(2y-1)^3\\\\\sqrt[3]{x}=2y-1\qquad\text{take cube root}\\\\\sqrt[3]{x}+1=2y\qquad\text{add 1}\\\\y=\dfrac{\sqrt[3]{x}+1}{2}\qquad\text{divide by 2}\\\\\boxed{f^{-1}(x)=\dfrac{\sqrt[3]{x}+1}{2}}](https://tex.z-dn.net/?f=x%3D%282y-1%29%5E3%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3D2y-1%5Cqquad%5Ctext%7Btake%20cube%20root%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%7D%2B1%3D2y%5Cqquad%5Ctext%7Badd%201%7D%5C%5C%5C%5Cy%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7Bx%7D%2B1%7D%7B2%7D%5Cqquad%5Ctext%7Bdivide%20by%202%7D%5C%5C%5C%5C%5Cboxed%7Bf%5E%7B-1%7D%28x%29%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7Bx%7D%2B1%7D%7B2%7D%7D)
