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Snezhnost [94]
3 years ago
12

If there is a break at any point in a series circuit the current will

Physics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

not work

Explanation:

in a series circuit, everything meaning the electrons are flowing on one path, therefore, it wouldn continue to work.

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If the caffeine concentration in a particular brand of soda is 2.97 mg/oz, 2.97 mg/oz, drinking how many cans of soda would be l
Ray Of Light [21]

Explanation:

The given data is as follows.

     Concentration of caffeine = 2.97 mg/oz

     Number of oz in a can = 12 oz

Therefore, the concentration of caffeine in one can is calculated as follows.

                 = (12 \times 2.97) mg

                 = 35.64 mg

                 = 35.64 \times 10^{-3} g

Since, it is given that lethal dose is 10.0 g. Hence, number of cans are calculated as follows.

     No. of cans = \frac{\text{Lethal dose}}{\text{concentration in one can}}

                         = \frac{10 g}{35.64 \times 10^{-3} g}

                         = 280.58

                         = 281 (approx)

Thus, we can conclude that 281 cans of soda would be lethal.

5 0
3 years ago
Torque is the rotational quantity most closely related to the linear quantity
jek_recluse [69]

Answer:

The definition of torque states that one or both of the angular velocity or the moment of inertia of an object are changing.

Velocity and momentum

Explanation:

4 0
3 years ago
You leave on a 450 miles trip in order to attend a meeting that will start 10.8 hours after you begin your trip. Along the way y
konstantin123 [22]

Answer:

c. 2.6 h

Explanation:

The longest time spent over dinner is the time that you have available minus the minimum possible time spent in the trip.

The time of the trip is found using:

t = \frac{d}{v}

Where distance is d and velocity is v. The time will be minimum at maximum velocity. Replacing with the data we have:

Ttrip = \frac{450}{55} = 8.1818 h

Tdinner = 10.8h - 8.1818 h = 2.6181h

that aproximates 2.6 h.

4 0
3 years ago
Which has more momentum: a 20,000 kg cement truck traveling at 5 m/s or a 1000 kg race car traveling at 90 m/s
Maurinko [17]

Hi there!

Recall the equation for momentum:
\large\boxed{p = mv}

p = linear momentum (kgm/s)
m = mass (kg)

v = velocity (m/s)

We can calculate each object's momentum and compare.

Cement truck:
p = 20000 \cdot 5 = 100000kg\frac{m}{s}

Race car:
p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}

<u>Since 100,000 > 90,000, the cement truck has the greater momentum.</u>

8 0
3 years ago
Force F=2.0N i - 3.0N k acts on a pebble with position vectorr=0.50m j - 2.0m k relative to the origin. In unit vector notation,
klasskru [66]

Answer with Explanation:

We are given that

Force acts on a pebble=2\hat{i}-3\hat{k} N

Position vector=r=0.5\hat{j}-2\hat{k} m

a.We have to find the resulting torque on the pebble about origin.

Torque=r\times F

Substitute the values then we get

Torque= (0.5j-2k)\times (2i-3k)

Torque=-k-1.5i-4jN-m

By using i\times j=k,j\times k=i,k\times i=j,j\times i=-k,k\times j=-i,i\times k=-j,i\times i=j\times j=k\times k=0

b.r=2i-3k

r-r_1=(0.5j-2k)-(2i-3k)=-2i+0.5j+k

Torque about point (2,0,-3)

\tau=(-2i+0.5j+k)\times (2i-3k)

\tau=-6j-k-1.5i+2j=-1.5i-4j-kN-m

6 0
3 years ago
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