<span>FACTS:
|
|
It’s
that time of year again when the days are wet and cool.
The rainy
season is the best season.
Rain makes up part of Earth’s water cycle.
Water evaporates from streams, lakes, and oceans, then condensation
and
precipitation occur in the form of rain.
Precipitation in the form of
rain is better than snow.
Snow this time of year makes people gloomy.
Rain is a great boon to local farmers.
It helps their crops grow.
</span>OPINIONS:
|
<span>| It’s
that time of year again when the days are wet and cool.
The rainy
season is the best season.
Rain makes up part of Earth’s water cycle.
Water evaporates from streams, lakes, and oceans, then condensation
and
precipitation occur in the form of rain.
Precipitation in the form of
rain is better than snow.
Snow this time of year makes people gloomy.
Rain is a great boon to local farmers.
It helps their crops grow.</span>
Answer:
0 J
Explanation:
given,
mass of the ball = 5 kg
radius of the horizontal circle = 0.5 m
tension in the string = 10 N
Work done = ?
Work done by the tension in the circular path will be equal to zero.
This is because body moves in circular path, the centripetal force act along the radius of the circle and motion is right angle to the tension on the string.
so, work done = F s cos θ
θ = 90°,
work done = F s cos 90° ∵ cos 90° = 0
Work done = 0 J
A = .3*g = 2.94 m/s²
<span>t = v/a = 9/2.94 = 3.061 sec </span>
<span>W = E/t = ½mv²/t = ½*40*9²/3.061 = 529.2 watts</span>
Answer:
the average force exerted by seatbelts on the passenger is 5625 N.
Explanation:
Given;
initial velocity of the car, u = 50 m/s
distance traveled by the car, s = 20 m
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 90 kg
Determine the acceleration of the car as it hit the pile of dirt;
v² = u² + 2as
0 = 50² + (2 x 20)a
0 = 2500 + 40a
40a = -2500
a = -2500/40
a = -62.5 m/s²
The deceleration of the car is 62.5 m/s²
The force exerted on the passenger by the backward action of the car is calculated as follows;
F = ma
F = 90 x 62.5
F = 5625 N
Therefore, the average force exerted by seatbelts on the passenger is 5625 N.
