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Dovator [93]
1 year ago
12

Question 2

Physics
1 answer:
Ksivusya [100]1 year ago
4 0

5.77 ×10^1^4 Hz is the green photon's frequency .

The distance between similar points (adjacent crests) in adjacent cycles of a waveform signal that is propagated in space is known as the wavelength. A wave's wavelength is often measured in meters (m), centimeters (cm), or millimeters (mm) (mm). The relationship between frequency and wavelength is inverse.

<h3>Given:</h3>

Wavelength of green light = 520 nm

f = c / λ

where, f = Frequency

            c = Speed of light = 3 × 10^8 m/s

            λ = Wavelength of light

∴ f = c / λ

  f = \frac{3*10^8}{520 * 10^-^9}

    = 5.77 ×10^1^4 Hz

Therefore,  5.77 ×10^1^4 Hz is the green photon's frequency .

Learn more about wavelength here:

brainly.com/question/10728818

#SPJ1

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<span>FACTS:
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It’s that time of year again when the days are wet and cool.
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Rain makes up part of Earth’s water cycle.
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</span>OPINIONS:
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<span>|         It’s that time of year again when the days are wet and cool.
The rainy season is the best season.
         Rain makes up part of Earth’s water cycle.
         Water evaporates from streams, lakes, and oceans, then condensation
            and precipitation occur in the form of rain.
Precipitation in the form of rain is better than snow.
Snow this time of year makes people gloomy.
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6 0
3 years ago
Read 2 more answers
A ball of mass 5 kg attached to a string is swung in a horizontal circle of radius 0.5 m. If the tension in the string is 10 N,
kirill115 [55]

Answer:

0 J

Explanation:

given,

mass of the ball = 5 kg

radius of the horizontal circle = 0.5 m

tension in the string = 10 N

Work done = ?

Work done by the tension in the circular path will be equal to zero.

This is because body moves in circular path, the centripetal force act along the radius of the circle and motion is right angle to the tension on the string.

so, work done = F s cos θ

     θ = 90°,

work done = F s cos 90°        ∵ cos 90° = 0

Work done = 0 J

8 0
3 years ago
A 18.0-kg rock is sliding on a rough, horizontal surface at 7.10 m/s and eventually stops due to friction. the coefficient of ki
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A = .3*g = 2.94 m/s² 

<span>t = v/a = 9/2.94 = 3.061 sec </span>

<span>W = E/t = ½mv²/t = ½*40*9²/3.061 = 529.2 watts</span>
4 0
2 years ago
Could someone tell me if this is right or give me the answers so i can re write them! That would be so helpful:)
Ivahew [28]

Answer:

Those are all right

Explanation:

6 0
3 years ago
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⦁ A car going 50 m/s is brought to rest in a distance of 20.0 m as it strikes a pile of dirt. How large an average force is exer
gtnhenbr [62]

Answer:

the average force exerted by seatbelts on the passenger is 5625 N.

Explanation:

Given;

initial velocity of the car, u = 50 m/s

distance traveled by the car, s = 20 m

final velocity of the after coming to rest, v = 0

mass of the passenger, m = 90 kg

Determine the acceleration of the car as it hit the pile of dirt;

v² = u² + 2as

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40a = -2500

a = -2500/40

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The force exerted on the passenger by the backward action of the car is calculated as follows;

F = ma

F = 90 x 62.5

F = 5625 N

Therefore, the average force exerted by seatbelts on the passenger is 5625 N.

8 0
3 years ago
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