Ask question

Ask question

All categories

2 years ago

14

Circle d has a radius of 21 millimeters and central angle, ∠edf, which measures 60°. find the exact length of . mm 7mm 14mm 42mm

2 answers:

maria [59]2 years ago

8 0

The length of an arc length can be calculated using the formula:
s = ra
where s is the lenght of the arc
and r is the radius of the circle
a is the central angle in radians

first converts degrees to radians
a = 60 ( pi / 180)
a = pi /3 =1.05

s = 21(1.05)
s = 22 mm is the length of the arc

mixer [17]2 years ago

8 0

Answer:

7π mm

Have a good day!

You might be interested in

Which of these numbers is a rational number?

Ymorist [56]

Answer:

the answer is A and C

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Would appreciate any help!! :D

Salsk061 [2.6K]

73+112+90=275
360-275=85
the angle of x is 85 degrees
(pls mark brainliest)

6 0

2 years ago

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

<u>Solving the trigonometry functions</u>

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

2 years ago

How many zeros in x^4 + 3x2 + 12

barxatty [35]

Answer:

We know that ,

Number of zeroes in a polynomial = degree of the polynomial

( degree of polynomial = the highest power in the polynomial )

therefore ,

$\bold\blue{number \:of \:zeroes \:of\: the \:given} \\\bold\blue{polynomial\: = \:4}$

hope helpful~

3 0

2 years ago

Write an exponential function to represent a person consuming a bag of candy in which the initial value in an is 175 pieces and

Alisiya [41]

We will see that the exponential decay function is:

f(x) = 175*(0.8)^x

<h3>How to find the exponential decay?</h3>

The general exponential decay is:

f(x) = A*(1- r)^x

Where:

A is the initial value.
r is the rate of decay in decimal form.
x is the variable, in this case is the time.

Here we know that the initial value is 175, and the rate of decay is 20%. To get this in decimal form, we just divide it by 100%.

20%/100% = 0.2

Replacing that in the exponential function, we get:

f(x) = 175*(1 - 0.2)^x

f(x) = 175*(0.8)^x

If you want to learn more about exponential functions, you can read:

brainly.com/question/11464095

5 0

2 years ago