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patriot [66]
3 years ago
15

Calculate the mass of magnesium oxide that is produced when 64 g of magnesium is combined with 1.32 g of oxygen

Chemistry
1 answer:
kirill [66]3 years ago
3 0
64 + 1.24 = 65.24 g of MgO
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A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74
stellarik [79]

Explanation:

Starting moles of ethanol acid = 0.020 mol

At the equilibrium 50 % of the ethanol acid molecules reacted

∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %

                                                                   = 0.010 mol

Moles of ethanol acid remain = 0.020 mol + 0.010 mol = 0.010 mol

Moles of the product (CH3COOH)^{2} gas formed are calculated as

0.010 mol CH3COOH * 1 mol (CH3COOH)^{2} / 2 mol CH3COOH

= 0.005 mol (CH3COOH)^{2}

Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol (CH3COOH)^{2}

That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol

Now Calculate the pressure  :

0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas

P1/n1 = P2/n2

P2 = P1*n2 / n1

      = 0.74 atm * 0.015 mol / 0.020 mol

     = 0.555 atm

4 0
3 years ago
Foxplain the term hybridizatim​
serg [7]

Answer:

Showing results for explain the term hybridization​

Search instead for foxplain the term hybridization​

Image result for explain the term hybridization​

In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.

Explanation:

6 0
2 years ago
ammonia gas is used as refrigerant 0.474 atm. Pressure is required to change 2000 cm3 sample of ammonia initially at 1.0 atm to
Andreas93 [3]

Answer: The pressure required is 0.474 atm

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}V}   (At constant temperature and number of moles)

The equation is,

{P_1V_1}={P_2V_2}

where,

P_1 = initial pressure of gas = 1.0 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2000cm^3

V_2 = final volume of gas = 4.22dm^3=4220cm^3    (1dm^3=1000cm^3)

Now put all the given values in the above equation, we get:

{1.0\times 2000}={P_2\times 4200}

P_2=0.474atm

The pressure required is 0.474 atm

5 0
2 years ago
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