A species that changes the rate of a reaction but is neither consumed nor changed is

Margaret [11]

Here is what Golgi looks like, so that you can look at the picture and describe it.
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Glad I could help, and good luck!
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7 0

3 years ago

(06.03 MC) A 50.0 mL sample of gas at 20.0 atm of pressure is compressed to 40.0 atm of pressure at constant temperature. What i

oee [108]

Answer:

New volume is 25.0 mL

Explanation:

Let's assume the gas sample behaves ideally.

According to combined gas law for an ideal gas-

$\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where, $P_{1}$ and $P_{2}$ represent initial and final pressure respectively

$V_{1}$ and $V_{2}$ represent initial and final volume respectively

$T_{1}$ and $T_{2}$ represent initial and final temperature (in kelvin) respectively

Here, $T_{1}=T_{2}$ , $V_{1}=50.0mL$ , $P_{1}=20.0atm$ and $P_{2}=40.0atm$

So, $V_{2}=\frac{P_{1}V_{1}T_{2}}{P_{2}T_{1}}=\frac{(20.0atm)\times (50.0mL)}{40.0mL}=25.0mL$

So, the new volume is 25.0 mL

6 0

3 years ago

Fill in the blanks for the following statements: The rms speed of the molecules in a sample of H2 gas at 300 K will be _________

Anna007 [38]

Answer : The rms speed of the molecules in a sample of $H_2$ gas at 300 K will be four times larger than the rms speed of $O_2$ molecules at the same temperature, and the ratio $\mu _{rms}(H_2)/\mu _{rms}(O_2)$ constant with increasing temperature.

Explanation :

Formula used for root mean square speed :

$\mu _{rms}=\sqrt{\frac{3RT}{M}}$

where,

$\mu _{rms}$ = rms speed of the molecule

R = gas constant

T = temperature

M = molar mass of the gas

At constant temperature, the formula becomes,

$\mu _{rms}=\sqrt{\frac{1}{M}}$

And the formula for two gases will be,

$\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{M_{O_2}}{M_{H_2}}}$

Molar mass of $O_2$ = 32 g/mole

Molar mass of $H_2$ = 2 g/mole

Now put all the given values in the above formula, we get

$\frac{\mu _{H_2}}{\mu _{O_2}}=\sqrt{\frac{32g/mole}{M_{2g/mole}}}=4$

Therefore, the rms speed of the molecules in a sample of $H_2$ gas at 300 K will be four times larger than the rms speed of $O_2$ molecules at the same temperature.

And the ratio $\mu _{rms}(H_2)/\mu _{rms}(O_2)$ constant with increasing temperature because rms speed depends only on the molar mass of the gases at same temperature.

5 0

3 years ago

Neutral atoms of argon, atomic number 18, have the same number of electrons as each of the following items except: Cl- S -2 K+ C

irinina [24]

Answer:

Ne.

Explanation:

Neutral argon, atomic number 18, has 18 electrons.

Cl⁻:

Neutral atom of Cl, atomic number 17, has 17 electrons.

When it gains electron and be Cl⁻, then it has 18 electrons a neutral Ar.

S²⁻:

Neutral atom of S, atomic number 16, has 16 electrons.

When it gains 2 electrons and be S²⁻, then it has 18 electrons a neutral Ar.

K⁺:

Neutral atom of K, atomic number 19, has 19 electrons.

When it losses electron and be K⁺, then it has 18 electrons a neutral Ar.

Ca²⁺:

Neutral atom of Ca, atomic number 20, has 20 electrons.

When it losses 2 electrons and be Ca²⁺, then it has 18 electrons a neutral Ar.

Ne:

It is a noble gas that has 10 electrons.

So, the right choice is: Ne.

3 0

3 years ago

In an atom the number of electron is what as the number of protons???

nydimaria [60]

The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons.

7 0

2 years ago