All categories

3 years ago

30 POINTS HELP Which idea was supported by Aristarchus, Copernicus, and Galileo?

Chemistry

2 answers:

anastassius [24]3 years ago

7 0

Answer:

Explanation:

Travka [436]3 years ago

4 0

Answer:

SO SORRY it took so long but the answer is B :)

Explanation:

Trust me and good luck :)

You might be interested in

What happens when the temperature of an object decreases?

NNADVOKAT [17]

We know, Kinetic energy (movement of the particle) is directly proportional to the temperature of the object. When you decrease the temperature, it's movement will also decrease and object particles move slower.

In short, Your Answer would be Option B

Hope this helps!

6 0

3 years ago

Read 2 more answers

Mg (s) + 2HCl (aq) → MgCl2 (aq) + H2 (g)

Naya [18.7K]

Mg(c) + 237shi (4z) ¥at h2)

8 0

3 years ago

Read 2 more answers

Which of the following is a legume?

nirvana33 [79]

Answer:

The answer to your question is Clover

Explanation:

Legumes are plants or the seed of plants. Legumes are harvested for human consumption, for livestock forage and silage.

These plants are also important during the Nitrogen cycle due to they fix nitrogen.

Examples of legumes are:

Beans, alfalfa, clover, lentils, peas, mesquite, carob, tamarind, peanuts, soybeans, etc.

5 0

3 years ago

Read 2 more answers

Please help me i will give brain list

inessss [21]

a)CH3-CH2-CH2-CH=CH2

b)CH3-CH2-CH2-CH2-CH2-CH2-CH3

c)CH≡C-CH2-CH2-CH2-CH3

d)CH3-CH2-CH2-CH2-CH2-CH2-CH=CH2

e)CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH2-CH3

give me brain list

7 0

3 years ago

Phosphorus pentachloride decomposes according to this equation. PCl5(g) equilibrium reaction arrow PCl3(g) + Cl2(g) An equilibri

melisa1 [442]

Answer:

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

Explanation:

The equilibrium constant will remain the same irrespective of the amount of reactant taken.

Let us calculate the equilibrium constant of the reaction.

Kc= $\frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}$

Let us calculate the moles of each present at equilibrium

$moles=\frac{mass}{molarmass}$

molar mass of PCl₅=208

molar mass of PCl₃=137

molar mass of Cl₂=71

moles of PCl₅ = $\frac{mass}{molarmass}=\frac{4.13}{208}=0.02$

moles of PCl₃= $\frac{mass}{molarmass}=\frac{8.87}{137}=0.06$

moles of Cl₂ = $\frac{mass}{molarmass}=\frac{2.90}{71}=0.04$

the volume is 5 L

So concentration will be moles per unit volume

Putting values

Kc = $\frac{\frac{0.06}{5}\frac{0.04}{5}}{\frac{0.02}{5}}=0.024$

Now if the same moles are being transferred in another beaker of volume 2L then there will change in the concentration of each as follow

$PCl_{5}--->PCl_{3}+Cl_{2}$

Initial 0.02 0.06 0.04

Change -x +x +x

Equilibrium 0.02-x 0.06+x 0.04+x

Conc. (0.02-x)/2 (0.06+x)/2 (0.04+x)/2

Putting values

0.024 = $\frac{(0.06+x)(0.04+x)}{(0.02-x)2}$

Solving

$(0.024(2)(0.02-x)=(0.06+x)(0.04+x)$

$0.00096-0.048x=0.0024+x^{2}+0.1x$

$0.148x+x^{2}+0.00144=0$

x = -0.01

so the new moles of

PCl₅ = 0.02 + 0.01 =0.03

PCl₃ = 0.06-0.01 = 0.05

Cl₂ = 0.04-0.01 = 0.03

mass of each will be:

mass= moles X molar mass

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

5 0

4 years ago