1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Burka [1]
3 years ago
12

What is the pH for a solution that has an OH ion

Chemistry
1 answer:
Basile [38]3 years ago
3 0
Assuming that you mean 10^-4 M then this would be basic and would have a pH of 10.

pOH = -log[OH].
So pOH = 4
pH=14-pOH
pH = 10
You might be interested in
Describe, in terms of electrons, the difference between a calcium atom and a calcium ion
DanielleElmas [232]

The Calcium atom has 2 valence electrons but a Calcium ion will have no electrons because it is a cation ion. Meaning that there are more protons than electrons. Also, the normal calcium symbol is Ca but the calcium ion is Ca²⁺

I hope this wasn't too late

3 0
3 years ago
How can I become good at General chemistry 2 college level course?
ELEN [110]
Add me in snap chat and you will be the topper in your collage


Salushi_7
8 0
4 years ago
Hydrazine (N2H4), a rocket fuel , reacts with oxygen to form nitrogen gas and water vapor. The reaction is represented with the
Serggg [28]

85.33 grams of hydrazine is needed for the reaction.

Rocket fuel contains the reaction between hydrazine and oxygen to break and form nitrogen and water vapour along with steam as it is an exothermic reaction.

<h3>How to calculate the hydrazine amount?</h3>

The reaction can be shown as:

\rm N_{2}H_{4}(l) + O_{2}(g) \rightarrow N_{2}(g) + 2H_{2}O(g)

From the periodic chart, it can be said that:

  • Mass of nitrogen = 14 gm
  • Mass of oxygen = 16 gm
  • Mass of hydrogen = 1 gm

The molar mass of hydrazine will be:

\begin{aligned} \rm Molar \;mass \;of \rm \;N_{2}H_{4}&= 2(14) + 4(1) \\\\&= 32 \;\rm grams\end{aligned}

Mass of water:

\begin{aligned}&= 2(1) + 16 \\\\&= 18 \;\rm grams\end{aligned}

From the reaction, it can be said that,

1 mole of \rm N_{2}H_{4} = 2 moles of \rm H_{2}O

32 grams of \rm N_{2}H_{4}  = ? grams of water

\begin{aligned}\text{Gram of water} &= 18 \times 2\\\\&= 36 \;\rm gm\end{aligned}

So, for 96 gm of water the hydrazine produced will be,

\begin{aligned}\text{mass of }\rm N_{2}H_{4} &= \dfrac{96 \times 32}{36}\\\\&= 85.3334 \;\rm grams \end{aligned}

Therefore, 85.33 grams of hydrazine is needed for the reaction.

Learn more about rocket fuel here:

brainly.com/question/10179270

7 0
2 years ago
As atoms get smaller,valance electrons are getting closer or farther away from the nucleous.The force of attraction is stronger
LiRa [457]

Explanation:

Electrons are closer to the nucleus are in filled orbitals and are called core electrons. More energy which in nucleus called nuclear strOng energy to remove electron thars why its also a way harder too..

3 0
3 years ago
Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p
UNO [17]

Answer : The equilibrium constant K_c for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of Br_2.

\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}

\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M

Now we have to calculate the dissociated concentration of Br_2.

The balanced equilibrium reaction is,

                              Br_2(g)\rightleftharpoons 2Br(aq)

Initial conc.         1.731 M      0

At eqm. conc.      (1.731-x)    (2x) M

As we are given,

The percent of dissociation of Br_2 = \alpha = 1.2 %

So, the dissociate concentration of Br_2 = C\alpha=1.731M\times \frac{1.2}{100}=0.2077M

The value of x = 0.2077 M

Now we have to calculate the concentration of Br_2\text{ and }Br at equilibrium.

Concentration of Br_2 = 1.731 - x  = 1.731 - 0.2077 = 1.5233 M

Concentration of Br = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

K_c=\frac{[Br]^2}{[Br_2]}

Now put all the values in this expression, we get :

K_c=\frac{(0.4154)^2}{1.5233}=0.1133

Therefore, the equilibrium constant K_c for the reaction is, 0.1133

7 0
3 years ago
Other questions:
  • Describe how Newton’s third law applies in a sports game. You choose the sport!
    11·2 answers
  • Why do scientists share the results of experiments
    11·2 answers
  • Identify the two layers of Earth where seismic S waves do not travel.
    14·2 answers
  • A tank containing both HF and HBr gases developed a leak. The ratio of the rate of effusion of HF to the rate of effusion of HBr
    10·2 answers
  • Students working in lab use 52.3g of CaCl2 to make a solution. When the solution is brought to a final volume of 800. mL, what i
    7·1 answer
  • Why are chemical changes considered “unseen”?
    5·2 answers
  • A.) What is the mass in g of 5 mols of Mg?
    5·1 answer
  • Problem 1:
    15·1 answer
  • How does the digestive system work with the muscular system?
    10·1 answer
  • Renewable energy resources include *
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!