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grin007 [14]
4 years ago
12

How did the pH level and the water components level change after adding water to the battery acid?

Chemistry
1 answer:
ololo11 [35]4 years ago
7 0
The pH level changed to 1.34 and the combination of the both made the mixture less acidic
the pH is 1.84, mixture had less acid and there is alot more water molecules in the mixture
the pH level is 2.13 ,, again less acidic and the water molecules has increased to 3,28 x10(25)
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A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the ca
BaLLatris [955]

Answer: The density of the liquid is 1.10g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of the unknown liquid  = 938 grams

Volume of the unknown liquid = 0.852L=852cm^3  (1L=1000cm^3

Putting in the values we get:

Density=\frac{938g}{852cm^3}

Density=1.10g/cm^3

Thus the density of the liquid is 1.10g/cm^3 and the liquid is dimethyl sulfoxide.

8 0
3 years ago
In fireworks, the heat of the reaction of an oxidizing agent, such as KClO₄, with an organic compound excites certain salts, whi
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6 0
2 years ago
Apply the law of conservation of mass to explain how mass is conserved when water evaporates 
frutty [35]
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8 0
4 years ago
When it became too hot to stay outside during a summer birthday party, the party was moved inside to an air-conditioned porch. I
harina [27]

Answer:

6.286 L.

Explanation:

Applying Charles Law,

V/T = V'/T'............................... Equation 1

Where V = Initial volume of the balloon, T = Initial Temperature of the balloon, V' = Final volume of the balloon, T' = Final Temperature of the balloon

make V' the subject of the equation

V' = VT'/T............................ Equation 2

Given: V = 6.50 L, T = 31 °C = (273+31) K = 304 K, T' = 21 °C = (273+21) K = 294 K

Substitute into equation 2

V' = 6.5(294)/304

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6 0
3 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
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