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RSB [31]
3 years ago
6

What will occur if a resistor with high resistance is inserted into a circuit?

Physics
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

<u>D. There will be a low current drop across it.</u>

Explanation:

The current may be substantially reduced by inserting a high resistance between two points (for the sake of this example, we'll use A and B). High resistances in an electrical current tend to reduce greatly the flow of charge, and they also have large potential drops across them.

Anton [14]3 years ago
5 0
If the resistor is in series with the rest of the circuit then a is the correct answer. The voltage across the resistor in series with another resistor is
V \frac{R}{R+r}
where R is the big resistor and r is the small one and V is the total voltage drop across both.  This is called a voltage divider
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If the energies sound in the device is microphone what is the energy out
Katen [24]

Answer:

Microphones are a type of transducer - a device which converts energy from one form to another. Microphones convert acoustical energy (sound waves) into electrical energy (the audio signal). Different types of microphone have different ways of converting energy but they all share one thing in common: The diaphragm.

Explanation:

5 0
3 years ago
The data table shows some data related to the Sun and the planets in our solar system.
AlexFokin [52]
You have selected the correct answer and blobbed over it with your pencil.

I assume you must have looked at Saturn's average distance, found 1427,
divided that number by 6, got 237 and change, then looked at the others,
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8 0
3 years ago
Read 2 more answers
The position of a particle as it moves along an y axis is given by y = (2.0cm)sin(πt/4), with t in second and y in centimeters.
irina [24]

Part a)

At t = 0  the position of the object is given as

x = 0

At t = 2

x = 2 sin(\pi/2) = 2cm

so displacement of the object is given as

d = 2 - 0 = 2cm

so average speed is given as

v_{avg} = \frac{2}{2} = 1 cm/s

Part b)

instantaneous speed is given by

v = \frac{dy}{dt}

v = 2cos(\pi t/4 ) * \frac{\pi}{4}

now at t= 0

v = \frac{\pi}{2} cm/s

at t = 1

v = 2 cos(\pi/4) * \frac{\pi}{4}

v = \frac{\pi}{2\sqrt2}

at t = 2

v = 0

Part c)

Average acceleration is given as

a_{avg} = \frac{v_f - v_i}{t}

a_{avg} = \frac{0 - \frac{\pi}{2}}{2}

a = -\frac{\pi}{4} cm/s^2

Part d)

Now for instantaneous acceleration

As we know that

a =- \omega^2 y

at t = 0

a = -\frac{\pi^2}{16} * 0 = 0 cm/s^2

at t = 1

y = \sqrt2 cm

now we have

a = -\frac{\pi^2}{16}*\sqrt2

At t = 2 we have

y = 2 cm

a = -\frac{\pi^2}{16}*2

a = -\frac{\pi^2}{8}

<em>so above is the instantaneous accelerations</em>

7 0
3 years ago
A 6 kg bowling ball is accelerated at a rate of 2.3 m/s² down the lane. How much force was necessary to produce this acceleratio
ira [324]
According to Newton's 2nd law of motion:
F = m * a where F is the force applied in Newtons, m is the mass of the object in kg, and a is the acceleration of the object in m/s^{2}.
Therefore the force applied in this situation is simply:
F = 6 kg * 2.3 m/s^{2} = 13.8 N
Hope this helps!
6 0
3 years ago
Which is not a way to accelerate an object?
GREYUIT [131]
<span>Slowing an object down is not a means of accelerating it. It actually decelerates the motion of an object. Speeding it up, changing its direction and applying balanced forces accelerate an object. In order for an object to accelerate, a force must be applied. It follows Newton’s second law of motion where it states that a body at rest remains at rest unless a force is acted upon it. When you move an object, you are exerting a force onto it. By exerting a force on the object, you are actually displacing it from its initial position. You cannot apply force to the object without altering its position. Keep in mind that when you exert work, you are exerting energy too. </span>
6 0
2 years ago
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