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3 years ago

Point M is the midpoint of AB . AM=3x+3, and AB=8x−6. What is the length of AM?

Mathematics

2 answers:

Scilla [17]3 years ago

8 0

AM = 21

Hope this helps :)

MissTica3 years ago

6 0

AM=3x+3
AB=8x-6
AB=2AM
AM=AB/2
AM=(8x-6)/2
AM=4x-3
3x+3=4x-3
4x-3x=3+3
x=6

AM=3x+3
AM=3(6)+3
AM=18+3
AM=21

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PLEASE HELP

kifflom [539]

$\\ \sf\longmapsto \dfrac{x^2-1}{x^2+5x+4}\leqslant 0$

Solving denominator

$\\ \sf\longmapsto x^2+5x+4>0$

$\\ \sf\longmapsto x^2+4x+x+4>0$

$\\ \sf\longmapsto x(x+4)+1(x+4)>0$

$\\ \sf\longmapsto (x+4)(x+1)>0$

$\\ \sf\longmapsto x>-4\:or x>-1$

Hence x $\neq$ -1
x can't be 0 as it makes function undefined

$\\ \sf\longmapsto -4$

5 0

2 years ago

How many times larger is 9 × 10^9 than 3 x 10^-4

ratelena [41]

<span> 9 × 10^9
---------------- = 3 x 10^13
</span><span>3 x 10^-4

answer
3 x 10^13 times larger</span>

3 0

2 years ago

Write the quadratic equation whose roots are -3 and 2 , and whose leading coefficient is 5

KiRa [710]

Step-by-step explanation:

Since, roots are - 3 & 2

Therefore, (x + 3) & (x - 2) would be factors.

Leading coefficient is 5

Hence, required quadratic equation is:

$5(x + 3)(x - 2) = 0 \\ \therefore \: 5( {x}^{2} - 2x + 3x - 6) = 0\\ \therefore \: 5( {x}^{2} + x - 6) = 0\\ \therefore \: 5 {x}^{2} + 5x - 30 = 0\: \\ is \: the \: required \: quadratic \: equation.$

5 0

3 years ago

E = {1, 2, 3, 4, 5, 6, 7, 8, 9

statuscvo [17]

Answer:

In the A circle: 1,3,8

In the B circle: 2

In the middle: 4,9

In the outside: 5,6,7

Hope this helps!

4 0

2 years ago

I really need help on this one, guys

Gennadij [26K]

Answer:

6.2 meters

Step-by-step explanation:

Use pythagorean theorem to find b:

b = √(2.8² - 2.7²) = √0.55 = 0.7 (nearest tenth)

Perimeter of triangle = sum of all its sides = 2.8 + 2.7 + 0.7

Perimeter = 6.2 meters

6 0

3 years ago