<h2>
Answer with explanation:</h2>
Let
be the population mean.
By observing the given information, we have :-

Since the alternative hypotheses is left tailed so the test is a right-tailed test.
We assume that the time spend by students per day is normally distributed.
Given : Sample size : n=121 , since n>30 so we use z-test.
Sample mean : 
Standard deviation : 
Test statistic for population mean :-


Critical value (one-tailed) corresponds to the given significance level :-

Since the observed value of z (-7.79) is less than the critical value (1.2816) , so we do not reject the null hypothesis.
Hence, we conclude that we have enough evidence to accept that the college students spend an average of 4 hours or less studying per day.
Answer:
12.5
Step-by-step explanation:
We want to find 1/8 of 100 so we would write it as 100÷8 to get 12.5
Now we know that 12.5 is equivalent to 1/8 but let's double check.
12.5×8 is 100
1/8 ×8 is 8/8
100=8/8
The answer is 20. you'll have to multiply 10 times 3 and get 30. Then you'll subtract the 10 from the 30 and get 20
Answer:
p=-7
Step-by-step explanation:
5p=-35
Divide both sides by 5
5p/5 =-35/5
therefore p=-7
C3=n
N x 2 - 6 + 2
N < (6x8) - 10