As per the question, the distance travelled by bobsled [s] = 100 m
The time taken by the bobsled to travel that distance [t] = 25 s
We are asked to calculate the speed of the bobsled.
The speed of the bobsled is calculated as -




Hence, the correct answer to the question is A. 4 m/s.
Answer:
<em>13.54 tons</em>
Explanation:
Let f be the amount of fuel oxidizer needed
v be the speed
The relationship between them is inverse in nature i.e
f ∝ 1/v
f = k/v
If a rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of 3.25 metric tons to a speed of 10,000 m/s, then f = 3.25 when v = 10,000
Substitute and get k
k = fv
k = 3.25 * 10,000
k = 32500
To get the amount of fuel oxidizer required to produce a speed of 2400m/s, we will find f when v = 2400m/s
Recall that f = k/v
f = 32500/2400
f = 13.54 metric tons
<em>Hence the fuel plus oxidizer that will be required is 13.54 tons</em>
Answer:
The type of decay illustrated by the equation is a Beta decay.
Option B is correct.
Explanation:
Complete Question
What type of decay is illustrated by the equation below?
²¹⁴₈₃Bi → ²¹⁴₈₄Po + ⁰₋₁e
- alpha decay
- beta decay
- positron emission
- electron capture
Solution
The type of radioactive decay is usually discernable from studying the products and reactants (the parent nucleus/atom, the daughter nucleus and the emitted or absorbed particles) of the radioactive decay.
The changes in atomic and mass numbers is accounted for in the particular particle that that is emitted and subsequently termed the type of radioactive decay that is going on.
For example, this equation represented shows that the Bi atom splits into a Po and a Beta particle. Hence, it is easy and straight forward to see that this radioactive decay is to relaese a Beta particle and the decay is a Beta decay.
(Note that, just as presented in the equation, a Beta particle has a mass number of 0 and an atomic number -1, kind of similar to an electron).
- An alpha decay releases an alpha particle.
- A beta decay releases a Beta particle.
- A positron emission releases a positron.
- An electron capture involves an electron attacking the parent atom/nucleus or the reactant.
Hope this Helps!!!
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