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algol13
3 years ago
15

How can you tell which substances are creating the light of the sun or a lightbulb?

Physics
1 answer:
Westkost [7]3 years ago
4 0
Through spectroscopy.  Each atom in a gas absorbs and emits light at very specific and unique frequencies.  Heating up a gas causes it to glow at these frequencies. If you put the light from a mercury lamp, for example, through a prism there will not be a rainbow.  There will only be specific bands of light at certain colors.  
On the other hand, white light comes from the sun.  The inner part of the sun creates white light as it isn't just a gas state (this specific choosing of frequencies is a gaseous phenomenon) but the atmosphere of the sun is a gas.  So when the white light passes through it, it absorbs specific frequencies specific to the elements in the gas.  These get scattered (released at random directions) and so many of them don't reach our telescopes.  So in a rainbow from stars (including the sun) have dark bands at specific frequencies.  You need equipment to focus and see the spectrum closely to notice this.  But the missing frequencies are the EXACT frequencies that the gas of the sun's atmosphere would release if heated in a lamp.  
So based on what light is emitted (in gas bulbs) or missing from a spectrum (from stars) we can tell what elements are present there.
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A uniform solid disk and a uniform ring are place side by side at the top of a rough incline of height h.
nadezda [96]

Explanation:

velocity of disc =\sqrt((gh)/0.75)

lets call (h) 1 m to make it simple.

= 3.614 m/s

\sqrt((4/3) x 1 x 9.8) = 3.614 m/s pointing towards this:

4×V_d=\sqrt(4/3hg)

V_h=\sqrt(hg)

velocity of hoop=\sqrt(gh)

lets call (h) 1m to make it simple again.

\sqrt(9.8 x 1) = 3.13 m/s

\sqrt(gh) = sqrt(hg)so [tex]4×V_d= \sqrt(4/3hg)V_h=\sqrt(hg)

The disc is the fastest.

While i'm on this subject i'll show you this:

Solid ball =0.7v^2= gh

solid disc = 0.75v^2 = gh

hoop =v^2=gh

The above is simplified from linear KE + rotational KE, the radius or mass makes no difference to the above formula.

The solid ball will be the faster of the 3, like above i'll show you.

solid ball: velocity =\sqrt((gh)/0.7)

let (h) be 1m again to compare.

\sqrt((9.8 x 1)/0.7) = 3.741 m/s

solid disk speed =\sqrt((gh)/0.75)

uniform hoop speed =\sqrt(gh)

solid sphere speed =\sqrt((gh)/0.7)

8 0
3 years ago
A basketball player achieves a hang time of
Citrus2011 [14]
The answer is 2.93m (to 2 dp)
6 0
4 years ago
What type of wave is produced when the frequency of a visible light wave is increased
SIZIF [17.4K]

-- If the frequency of a wave is too high for our eyes to detect it ... but not <u>too too</u> high ... we call it an <em>ultraviolet </em>wave.

-- If the wave's frequency is even higher than that, we call it an <em>X-ray</em> wave.

-- If the wave's frequency is even higher than that, we call it a <em>Gamma Ray </em>wave.

7 0
3 years ago
Ninety percent of stars in the solar system are :
sergiy2304 [10]
90% of stars in the solar system are main sequence stars.
3 0
3 years ago
The near point of an eye is 110 cm. A corrective lens is to be used to allow this eye to focus clearly on objects 26.0 cm in fro
irga5000 [103]

Answer:

The focal length of the lens is 34.047 cm

The power of the needed corrective lens is 2.937 diopter.

Explanation:

Distance of the object from the lens,u = 26 cm

Distance of the image from the lens ,v= -110 cm

(Image is forming on the other side of the lens)

Since ,lens of the human eye is converging lens,convex lens.

Using a lens formula:

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

\frac{1}{f}=\frac{1}{26 cm}+\frac{1}{-110 cm}

f = 34.047 cm = 0.3404 m

Power of the lens = P

P=\frac{1}{f}=\frac{1}{0.34047 m}=2.937 diopter

6 0
3 years ago
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