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emmainna [20.7K]
3 years ago
5

HELP!! I don’t understand this one bit

Chemistry
1 answer:
Mama L [17]3 years ago
3 0

Answer:

for this qn, you need to find out who is the limiting reagent. in this case i will do it this way.

if 49.6g of potassium hydrogen sulfate is present, 49.6g of potassium hydroxide is required. thus, there are lesser amt of potassium sulfate present than required thus KOH is the limiting reagent. if you do it the opposite way, you will realise there are MORE potassium hydrogen sulfate present than required, thus the another party, KOH, is limiting.

the next part you need to convert to mole but i am not really gd at it.

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1. A student in lab measures 4.6 grams of copper for an experiment. Upon further analysis he determines that he should have meas
Reil [10]

Answer:

2.13\%

Explanation:

Quantity of copper measured by a student = 4.6 grams

Original quantity of copper = 4.7 grams

Error in measurement = Original quantity of copper - Quantity of copper measured by a student  =4.7-4.6=0.1 grams

To find the percent error, apply the following formula:

Percent error = (Error in measurement / Original quantity of copper) × 100

=\frac{0.1}{4.7}(100)=2.13\%

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4 years ago
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3 years ago
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STALIN [3.7K]

Answer:

particles in solids are always vibrating (moving back and forth) in place the vibrational motion of particles in solids is kinetic energy heat makes the particles in a solid vibrate faster, giving them more kinetic energy faster-vibrating particles bump into one another more often and hit each other harder

4 0
3 years ago
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Answer: The answer is B

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5 0
3 years ago
A gas mixture with a total pressure of 750 mmHg contains each of the following gases at the indicated partial pressures: CO2 , 1
jolli1 [7]

Answer: a) 211 mm Hg

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Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_1+p_2+p_3+p_4

p_{total} = total pressure = 750 mmHg

p_{CO_2} = 124 mm Hg

p_{Ar} = 218 mm Hg

p_{O_2} = 197 mm Hg

p_{He} = ?

750 mmHg=124 mm Hg+218 mm Hg+197 mm Hg+p_{He}

p_{He}=211mmHg

Thus  the partial pressure of the helium gas is 211 mmHg.

b) According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 211 mmHg = 0.28 atm   (760mmHg=1atm)

V= Volume of the gas = 13.0 L

T= Temperature of the gas =  282 K  

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= ?

n=\frac{PV}{RT}=\frac{0.28\times 13.0}0.0821\times 282}=0.157moles

Mass of helium= moles\times {\text {molar mass}}=0.157\times 4=0.629g

Thus mass of helium gas present in a 13.0-L sample of this mixture at 282 K is 0.629 grams

8 0
4 years ago
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