1.Calculate the molarity of a 6.15% (w/v%) sodium hypochlorite (NaOCl) solution (i.e. in a 100 ml of solution there is 6.15 gram
s of NaOCl.A. For each order (0th, first, second), give the integrated form of the rate law and explain what you would graph in order to test for that order.B. Calculate the molarity of a solution of Allura red AC, (FD&C dye Red #40) (MW 496.4 g/mol) if a 0.3500 g sample is diluted to 100 mL in a volumetric flask.C. You will be taking 3 ml of this solution and diluting to 100 mL in a volumetric flask. This will be solution 2. What is the molarity of solution 2?D. If you were to make a third solution by taking 3 ml of solution 2 and diluting it to 100 mL, what is the molarity of solution 3?Given:Solution 1. (Already prepared for you) (0.3500 g of food coloring in a 100-mL volumetric flask).Solution 2. Transfer 3 mL of Solution 1 to the 100-mL volumetric flask. Add DI water to fill to the mark. Label this solution as “Solution 2”Sodium Hypochlorite. Obtain about 5 mL of concentrated bleach (record the concentration of the bleach in your notebook) in a clean 50 mL beaker then add 45 mL of DI water. Label as “bleach”.
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Answer:
By heating the solution a saturated solution can be changed into an unsaturated solution. Without adding any solvent it can be changed into an unsaturated solution. Example: on heating a saturated solution of sugar in high temperature, it starts dissolving.
The answer should be neutrons electrons and protons
Answer: It is a molecular compound. (2) It contains a metal. (3) It can conduct electricity as a solid.
2AgNO3 (aq) + Na2CO3 (aq) --> Ag2CO3 (s) + 2NaNO3 (aq)
2Ag(+) (aq) + CO3(2-) (aq) --> Ag2CO3 (s)
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