1.Calculate the molarity of a 6.15% (w/v%) sodium hypochlorite (NaOCl) solution (i.e. in a 100 ml of solution there is 6.15 gram
s of NaOCl.A. For each order (0th, first, second), give the integrated form of the rate law and explain what you would graph in order to test for that order.B. Calculate the molarity of a solution of Allura red AC, (FD&C dye Red #40) (MW 496.4 g/mol) if a 0.3500 g sample is diluted to 100 mL in a volumetric flask.C. You will be taking 3 ml of this solution and diluting to 100 mL in a volumetric flask. This will be solution 2. What is the molarity of solution 2?D. If you were to make a third solution by taking 3 ml of solution 2 and diluting it to 100 mL, what is the molarity of solution 3?Given:Solution 1. (Already prepared for you) (0.3500 g of food coloring in a 100-mL volumetric flask).Solution 2. Transfer 3 mL of Solution 1 to the 100-mL volumetric flask. Add DI water to fill to the mark. Label this solution as “Solution 2”Sodium Hypochlorite. Obtain about 5 mL of concentrated bleach (record the concentration of the bleach in your notebook) in a clean 50 mL beaker then add 45 mL of DI water. Label as “bleach”.
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<span>19. Single displacement reactions are always redox reactions (they include reaction between an element and a compound where they will take place of another element in that compound).
20. It should be single displacement, where the displaced ion would form gas.</span>
On the first graph the beginning flat line is the reaction. Then comes the hill will it be call the activation energy. The final flat line would be the produce. Same names apply to the 2 graph too
Answer is: <span>the mass of the excess reactant (ethane) leftover is 90.135 grams.
</span>Chemical reaction: 2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O<span>(g).
m(</span>C₂H₆) = 152 g.
n(C₂H₆) = m(C₂H₆) ÷ M(C₂H₆).
n(C₂H₆) = 152 g ÷ 30 g/mol.
n(C₂H₆) = 5.067 mol.
m(O₂) = 231 g.
n(O₂) = 231 g ÷ 32 g/mol.
n(O₂) = 7.218 mol; limiting reactant.
From chemical reaction: n(O₂) : n(C₂H₆) = 7 : 2.
n(C₂H₆) = 2 · 7.218 mol ÷ 7.
n(C₂H₆) = 2.0625mol.
Δn(C₂H₆) = 5.067 mol - 2.0625 mol.
Δn(C₂H₆) = 3.0045 mol.
Δm(C₂H₆) = 3.0045 mol · 30 g/mol = 90.135 g.
Answer:
Any conductor (thing that electricity can go through) is made of atoms. Each atom has electrons in it. If you put new electrons in a conductor, they will join atoms, and each atom will deliver an electron to the next atom. This next atom takes in the electron and sends out another one on the other side.
Explanation:
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80% carbon and 20.% is hydrogen
