1.Calculate the molarity of a 6.15% (w/v%) sodium hypochlorite (NaOCl) solution (i.e. in a 100 ml of solution there is 6.15 gram
s of NaOCl.A. For each order (0th, first, second), give the integrated form of the rate law and explain what you would graph in order to test for that order.B. Calculate the molarity of a solution of Allura red AC, (FD&C dye Red #40) (MW 496.4 g/mol) if a 0.3500 g sample is diluted to 100 mL in a volumetric flask.C. You will be taking 3 ml of this solution and diluting to 100 mL in a volumetric flask. This will be solution 2. What is the molarity of solution 2?D. If you were to make a third solution by taking 3 ml of solution 2 and diluting it to 100 mL, what is the molarity of solution 3?Given:Solution 1. (Already prepared for you) (0.3500 g of food coloring in a 100-mL volumetric flask).Solution 2. Transfer 3 mL of Solution 1 to the 100-mL volumetric flask. Add DI water to fill to the mark. Label this solution as “Solution 2”Sodium Hypochlorite. Obtain about 5 mL of concentrated bleach (record the concentration of the bleach in your notebook) in a clean 50 mL beaker then add 45 mL of DI water. Label as “bleach”.
1 answer:
You might be interested in
Answer:
The reference ranges for blood potassium levels are as follows : Adult/elderly: 3.5-5.0 mEq/L or 3.5-5.0 mmol/L (SI units) Child: 3.4-4.7 mEq/L. Infant: 4.1-5.3 mEq/L.
Explanation:
Answer: i think the best bet i can give you is Option C (2:3)
Explanation: i apologize i haven't done chem in 2 years
but however to put it in retrospect the finished equation is 2(AL)^+3 3(O)^-2
Answer:
Explanation:
exothermic reactions involve release of heat whereas endothermic reaction involve absorption of heat.
Because they have similar attractive forces in their molecules
Answer:
it's
C. with melting point 11° C and boiling point 181° C
Explanation:
i hope you got it