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3 years ago

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Physics

2 answers:

Marta_Voda [28]3 years ago

3 0

Answer:

7200 m

Explanation:

The pond is 4000 meters away. The woman runs at 2.5 m/s. The time it takes her to reach the pond is:

t = 4000 m / 2.5 m/s

t = 1600 s

The dog is running at 4.5 m/s this entire time. So the distance he runs is:

d = 1600 s × 4.5 m/s

d = 7200 m

olga nikolaevna [1]3 years ago

3 0

Answer:

7200 m

Explanation:

A woman takes her pet dog on a walk to a pond which is 4km away. The woman runs with a speed of 2.5 ms-1 while the dog runs with the speed of 4.5ms^-1 towards the pond and returns to the women and then again runs back to the pond continuously until the woman also manages to reach the pond. The total distance traveled by the dog is 7200 m.

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You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe

steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, $L=800\ mH=800\times 10^{-3}\ H=0.8\ H$

Capacitance, $C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F$

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

$Z=\sqrt{R^2+(X_C-X_L)^2}$ ...........(1)

Where

$X_C$ is the capacitive reactance, $X_C=\dfrac{1}{2\pi fC}$

$X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega$

$X_L$ is the inductive reactance, $X_L={2\pi fL}$

$X_L={2\pi \times 60\times 0.8}=301.59\ \Omega$

So, equation (1) becomes :

$Z=\sqrt{(100)^2+(265.65-301.59)^2}$

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A projectile is launched from the ground at an angle of 60o above the horizontal. At what point in its trajectory does it have t

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Answer:

It's constant everywhere in its trajectory.

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the projectile was launched with an initial velocity, the only acceleration that is affecting the projectile's velocity is gravity.

The acceleration of gravity is practically equal everywhere on earth, so during its trajectory, we have to take into consideration only the acceleration because of gravity.

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2 years ago

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Answer:

frequency 1 = 334.30 Hz

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Given data

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lowest two frequencies

solution

we know velocity of sound is 343 m/s

so we consider point x

so at 1st speaker distance from x = D + (y/2)

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at 2nd speaker distance from x = D - (y/2)

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