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ankoles [38]
3 years ago
8

Help!?

Physics
2 answers:
Marta_Voda [28]3 years ago
3 0

Answer:

7200 m

Explanation:

The pond is 4000 meters away.  The woman runs at 2.5 m/s.  The time it takes her to reach the pond is:

t = 4000 m / 2.5 m/s

t = 1600 s

The dog is running at 4.5 m/s this entire time.  So the distance he runs is:

d = 1600 s × 4.5 m/s

d = 7200 m

olga nikolaevna [1]3 years ago
3 0

Answer:

7200 m

Explanation:

A woman takes her pet dog on a walk to a pond which is 4km away. The woman runs with a speed of 2.5 ms-1 while the dog runs with the speed of 4.5ms^-1 towards the pond and returns to the women and then again runs back to the pond continuously until the woman also manages to reach the pond. The total distance traveled by the dog is 7200 m.

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juin [17]

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Explanation: The arrows are going 15 m west and 7.0 m east. 7 meters of the west will cancel out because 15-7=8. Subtract the smaller number from the bigger number, which is west minus east. The answer will be 8.0 m west.

5 0
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A scientist makes a device to catch baseballs. A long bar of total mass 2.2kg and length 1.2m is fixed at its center. It catches
Valentin [98]

Answer:

ωf = 4.53 rad/s

Explanation:

By conservation of the angular momentum:

Ib*ωb = (Ib + Ic)*ωf

Where

Ib is the inertia of the ball

ωb is the initial angular velocity of the ball

Ic is the inertia of the catcher

ωf is the final angular velocity of the system

We need to calculate first Ib, Ic, ωb:

Ib = mb*(L/2)^2=0.15*(1.2/2)^2=0.054 kg.m^2

Ic = mc/12*L^2=2.2/12*1.2^2=0.264 kg.m^2

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\omega f = \frac{Ib*\omega b}{Ib + Ic}  = 4.53rad/s

8 0
3 years ago
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dem82 [27]

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Explanation:

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How long does a dream typically last near the end of the sleep cycle, just before waking?
matrenka [14]
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4 years ago
A 15 g toy car moving to the right at 24 cm/s has a head-on nearly elastic collision with a 21 g toy car moving in the opposite
11111nata11111 [884]

Answer:

The speed of the second toy car after collision is v_2 = 0.155 \ m/s

Explanation:

Let movement to the right be positive and the opposite negative

From the question we are told that

   The mass of the car is  m_1 =  15 \ g =  \frac{15}{1000}  =  0.015 \ kg

    The initial velocity of the car is  u_1 =  24 \ cm /s  =  0.24 m/s

    The mass of the second toy car  m_2 = 21 g =  0.021 \ kg

    The initial velocity of the car is u_2 =  31 \ cm/s =- 0.31 m/s

    The final velocity of the first car is  v = 41cm/s = - 0.41 m/s

     From law of momentum conservation we have that

     m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

substituting values

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      v_2 = 0.155 \ m/s

 

3 0
3 years ago
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