Answer: A
<u>Explanation:</u>
NOTES:
d = 650 meters
t = 10 seconds
**********************************
v = d/t
= 650 meters/10 seconds
= 65 meters/second
Answer:
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Explanation:
Answer:
distance r from the uranium atom is 18.27 nm
Explanation:
given data
uranium and iron atom distance R = 44.10 nm
uranium atom = singly ionized
iron atom = doubly ionized
to find out
distance r from the uranium atom
solution
we consider here that uranium electron at distance = r
and electron between uranium and iron so here
so we can say electron and iron distance = ( 44.10 - r ) nm
and we know single ionized uranium charge q2= 1.602 ×
C
and charge on iron will be q3 = 2 × 1.602 ×
C
so charge on electron is q1 = - 1.602 ×
C
and we know F =
so now by equilibrium
Fu = Fi
=
put here k =
and find r
=

r = 18.27 nm
distance r from the uranium atom is 18.27 nm
A is the correct answer, pls give brainliest
The kinetic energy of the ejected electrons will be 2782.5 ×10⁻²² eV.
<h3>What is threshold frequency?</h3>
The threshold frequency of incoming radiation is the lowest frequency at which photoelectric emission or electron emission is impossible.
The threshold frequency is the light frequency that causes an electron to dislodge and emit from the metal's surface.
From the photoelectric effect, the equation obtained as;

Hence,the kinetic energy of the ejected electrons will be 2782.5 ×10⁻²² eV.
To learn more about the threshold frequency, refer to the link;
brainly.com/question/2499414
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