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3 years ago

PLZ HLP I DONT KNOW

Mathematics

2 answers:

astraxan [27]3 years ago

4 0

The answer is 7 because if you add 2+2-2+2x3-5

bekas [8.4K]3 years ago

3 0

It’s 1 hope it helps

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What's three fourths times twenty eight equal?

Hoochie [10]

Hi , 3/4 times 28 equals to 84/4
28 is equivalent to 28/1
we just multiply straight across
28 x 3 equals to 84
4 x 1 equals to 4

5 0

3 years ago

Read 2 more answers

Please help!!No links

shepuryov [24]

X=12 do you need an explanation?

8 0

3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

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$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus

7 0

3 years ago

Need help with the answer please and thank you NO LINKS! Have a nice day

KIM [24]

Answer: 188+22x=518 (c)

Step-by-step explanation:

7 0

2 years ago

Factorise by grouping: x² - 5x + 2x - 10

IrinaK [193]

Answer:

(x + 2)(x - 5)

Step-by-step explanation:

Here are the steps:

$x^2-5x+2x-10\\(x^2-5x)+(2x-10)\\x(x-5) + 2(x-5)\\(x + 2)(x-5)$

4 0

3 years ago