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emmasim [6.3K]
3 years ago
6

PLZ HLP I DONT KNOW

Mathematics
2 answers:
astraxan [27]3 years ago
4 0
The answer is 7 because if you add 2+2-2+2x3-5
bekas [8.4K]3 years ago
3 0
It’s 1 hope it helps
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Find the area of the composite figure.
Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

\boxed{ \rm \: Area  \:  of \:  Rectangle = Length×Breadth}

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

\boxed{\rm \: Breadth = total  \: distance - Radius}

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

\longrightarrow\rm \: Length \:  of \:  the  \: circle = Radius

  • Since Length = 6 in ;

\longrightarrow \rm \: 6 \: in   = radius

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

  • Total Horizontal Distance= 14
  • Radius = 6

\longrightarrow\rm \: Breadth = 14-6

\longrightarrow\rm \: Breadth = 8 \: in

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

  • Length = 6
  • Breadth = 8

\longrightarrow\rm \: Area \:  of  \: Rectangle = 6 \times 8

\longrightarrow \rm \: Area \:  of  \: Rectangle = 48 \: in {}^{2}

Then, We need to find the area of Quarter circle :

We know that,

\boxed{\rm Area_{(Quarter \; Circle) }  = \cfrac{\pi{r} {}^{2} }{4}}

Now Substitute their values:

  • r = radius = 6
  • π = 3.14

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 6 {}^{2} }{4}

Solve it.

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times 36}{4}

\longrightarrow\rm Area_{(Quarter \; Circle) } =  \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}

\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9

\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \:  {in}^{2}

Now we can Find out the total Area of composite figure:

We know that,

\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}

So Substitute their values:

  • \rm Area_{(rectangle)} = 48
  • \rm Area_{(Quarter Circle)} = 28.26

\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26

Solve it.

\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

\rule{225pt}{2pt}

I hope this helps!

3 0
2 years ago
I need help with this I am giving 60 points
inna [77]

Answer:

<2 ≅<4 with reason of vertical angle theorem.

Step-by-step explanation:

The vertical angle theorem states that two opposite (non-adjacent) angles formed by 2 intersecting lines have equal measure. In this problem, we are given that the angles are vertical angles. So the statement is that <2 ≅<4 with reason of vertical angle theorem.

3 0
3 years ago
What is the y-intercept of the line shown below? Enter your answer as a coordinate pair.
jolli1 [7]

Answer:

The x intercept is (-2,0)

the y intercept is (0,4)

7 0
2 years ago
Help me please don't know
dem82 [27]
1. 5 x 5
2. 7 x 28
3. 90 divided by 70
4. 40 divided by 5.
Hope this helps. #I'm11
8 0
3 years ago
The following table represents the highest educational attainment of all adult residents in a certain town. If a resident who ha
FromTheMoon [43]

Answer:

=0.291

Step-by-step explanation:

number of residents who have completed some college =5372

number of residents who has completed college and age group 20-29years=1563

1563/5372

=0.29095

6 0
2 years ago
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