Answer:
42.24 psi.
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 29.72 psi
Initial volume (V₁) = 10.22 L
Final volume (V₂) = 7.19 L
Final pressure (P₂) =?
The final pressure can be obtained by applying the Boyle's law equation as follow:
P₁V₁ = P₂V₂
29.72 × 10.22 = P₂ × 7.19
303.7384 = P₂ × 7.19
Divide both side by 7.19
P₂ = 303.7384 / 7.19
P₂ = 42.24 psi
Therefore, the final pressure is 42.24 psi
Answer:
28atm
Explanation:
Using Gay lussac's law equation as follows:
P1/T1 = P2/T2
Where;
P1 = initial pressure (atm)
T1 = initial temperature (K)
P2 = final pressure (atm)
T2 = final temperature (K)
Based on the information provided in this question;
P1 = 30.0 atm, T1 = 30.0°C, P2 = ?, T2 = 10.0°C
NOTE: Absolute temperature i.e. Kelvin is required for this law
T1 = 30°C + 273K = 303K
T2 = 10°C + 273K = 283K
Using P1/T1 = P2/T2
30/303 = P2/283
Cross multiply
P2 × 303 = 30 × 283
303P2 = 8490
P2 = 8490/303
P2 = 28.02
New pressure of the gas = 28atm
Answer:
certain types of plants (vascular plants) have a system for transporting water, minerals
Answer:
of water at 30C and 1 atm is 256.834 J/mol·K.
Explanation:
To solve the question, we note the Maxwell relation such as
Where:
= Specific heat of gas at constant pressure = 75.3 J/mol·K
= Specific heat of gas at constant volume = Required
T = Temperature = 30 °C = 303.15 K
α = Linear expansion coefficient = 3.04 × 10⁻⁴ K⁻¹
K = Volume comprehensibility = 4.52 × 10⁻⁵ atm⁻¹
Therefore,
75.3 - 
= 
= - 75.3 = 256.834 J/mol·K.
<u>Answer:</u> The final temperature of the copper is 95°C.
<u>Explanation:</u>
To calculate the final temperature for the given amount of heat absorbed, we use the equation:
Q = heat absorbed = +133 J (heat is added to the system)
m = mass of copper = 5.00 g
c = specific heat capacity of copper = 0.38 J/g ° C
Putting values in above equation, we get:
Hence, the final temperature of the copper is 95°C.
