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Ratling [72]
3 years ago
15

____is a software application used to locate and display Web pages.

Chemistry
2 answers:
kenny6666 [7]3 years ago
5 0

Answer:

Ans: A web browser

Explanation:

A web browser is a software that can be used to look at web pages on the internet

Blababa [14]3 years ago
4 0

Answer:

\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}

Browser

Browser: A software application used to locate and display Web pages. The two most popular browsers are Microsoft Internet Explorer and Netscape Navigator

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50. A 51. D 52. B 53. B 54. C

Explanation: solution attached.

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Plants and animals add carbon dioxide to the atomsphere when they ____ glucose.
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10. (a) Describe how the structure of an alloy is different to a pure metal
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1.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
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(1 Point)
an element that reacts with water to produce a lilac flame

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an element used as an inert atmosphere

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(1 Point)
an element that has a valency of 3

4.Write a balanced chemical equation for the reaction between potassium and water. (Non-anonymous question). .
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Upload file
File number limit: 1Single file size limit: 10MBAllowed file types: Word, Excel, PPT, PDF, Image, Video, Audio
5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
Elements may be used once, more than once or not all.. Single line text.
(1 Point)
an element with a fixed valency of 2 that not is not in group 2

Help
4 0
3 years ago
Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma
Elena-2011 [213]

Answer:

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

Explanation:

CaCO_3(s)\rightarrow CaO(s) + CO_2(g)

Annual production of CaO = 8.6\times 10^{10} kg=8.6\times 10^{13} g

Moles of CaO :

\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with  1.53\times 10^{12} moles of CaO moles of carbon-dioxide moles produced will be:

\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles of carbon-dioxide

Mass of 1.53\times 10^{12} moles of carbon-dioxide:

1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

6 0
3 years ago
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