Answer:
<em>By showing that changing the frequency of light causes the emission of faster electrons.
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Explanation:
<em>The photoelectric effect happens when light strikes a metal surface causing the emission of electrons from it (photoelectrons).
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<em>If you increase the intensity of the light you get, as acresult, more electrons emitted but their kinetic energy does not increase.
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<em>If you increase the frequency of the incident light the number of photoelectrons emitted does not increase while the velocity, and so their kinetic energy, increases...the emitted electrons are more...energetic!
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<em>This can be explained considering the incident light as a shower of particle-like packets of energy (photons); if you increase the intensity you simply increase the number of packets (all with the same energy) hitting the metal; these can be used by a lot of electrons to escape.
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<em>On the other hand if you increase the frequency the number of packets remains the same (emitting fewer electrons perhaps) but the energy carried by each of them increases.
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<em>Each packet carries an energy directly proportional to the frequency.</em>
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Answer:
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Explanation:
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In physics, net force<span> is the overall </span>force<span> acting on an object. In order to calculate the </span>net force<span>, the body is isolated and interactions with the environment or other constraints are represented as </span>forces<span> and torques in a free-body diagram.
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Answer:
We need 8.11 grams of glucose for this solution
Explanation:
Step 1: Data given
Molarity of the glucose solution = 0.300 M
Total volume = 0.150 L
The molecular weight of glucose = 180.16 g/mol
Step 2: Calculate moles of glucose in the solution
Moles glucose = molarity solution * volume
Moles glucose = 0.300 M * 0.150 L
Moles glucose = 0.045 moles glucose
Step 3: Calculate mass of glucose
MAss glucose = moles glucose* molecular weight of glucose
MAss glucose = 0.045 moles * 180.16 g/mol
MAss glucose = 8.11 grams
We need 8.11 grams of glucose for this solution
On temperature 25°C (298,15K) and pressure of 1 atm each gas has same amount of substance:
n(gas) = p·V ÷ R·T = 1 atm · 20L ÷ <span>0,082 L</span>·<span>atm/K</span>·<span>mol </span>· 298,15 K
n(gas) = 0,82 mol.
1) m(He) = 0,82 mol · 4 g/mol = 3,28 g.
d(He) = 10 g + 3,28 g ÷ 20 L = 0,664 g/L.
2) m(Ne) = 0,82 mol · 20,17 g/mol = 16,53 g.
d(Ne) = 26,53 g ÷ 20 L = 1,27 g/L.
3) m(CO) = 0,82 mol ·28 g/mol = 22,96 g.
d(CO) = 32,96 g ÷ 20L = 1,648 g/L.
4) m(NO) = 0,82 mol ·30 g/mol = 24,6 g.
d(NO) = 34,6 g ÷ 20 L = 1,73 g/L.
