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3 years ago

Which property of ionic bonds is illustrated on the right? What other physical properties does this structure affect?

Chemistry

1 answer:

aniked [119]3 years ago

4 0

Answer:

Crystal structure; brittleness

Step-by-step explanation:

The image illustrates the crystal structure of an ionic solid.

This structure affects the brittleness of the solid.

If you strike a sharp blow to the crystal with a hammer, the crystal layers will slide past each other.

The ions with the same charge will repel each other, and the crystal will fly apart.

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If the freezing point of an aqueous 0.10 m glucose solution is −x°c, what is the approximate freezing point of a 0.10 m nacl sol

maks197457 [2]

Answer is: the approximate freezing point of a 0.10 m NaCl solution is -2x°C.
Van't Hoff factor (i) for NaCl solution is approximately 2.
Van't Hoff factor (i) for glucose solution is 1.
Change in freezing point from pure solvent to solution: ΔT = i · Kf · m.
Kf - molal freezing-point depression constant for water is 1,86°C/m.
m - molality, moles of solute per kilogram of solvent.
Kf and molality for this two solutions are the same, but Van't Hoff factor for sodium chloride is twice bigger, so freezing point is twice bigger.

8 0

3 years ago

Please comment the correct answer and I'll give you brainliest! Which atom of each pair below has the largest ionization energy?

monitta

Answer:kffffffffffffffffp;j.,,j,j[[;'/n m

Explanation:

tggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg00000000000

6 0

3 years ago

Read 2 more answers

If 500.0 ml of 0.10 m ca2+ is mixed with 500.0 ml of 0.10 m so42−, what mass of calcium sulfate will precipitate? ksp for caso4

attashe74 [19]

Answer : The mass of calcium sulfate precipitate will be, 6.12 grams

Solution :

First we have to calculate the moles of $Ca^{2+}$ and $SO_4^{2-}$ .

$\text{Moles of }Ca^{2+}=\text{Molarity of }Ca^{2+}\times \text{Volume of }Ca^{2+}=0.10mole/L\times 0.5L=0.05\text{ moles}$

$\text{Moles of }SO_4^{2-}=\text{Molarity of }SO_4^{2-}\times \text{Volume of }SO_4^{2-}=0.10mole/L\times 0.5L=0.05\text{ moles}$

As, 0.05 moles of $Ca^{2+}$ is mixed with 0.05 moles of $SO_4^{2-}$ , it gives 0.05 moles of calcium sulfate.

Now we have to calculate the solubility of calcium sulfate.

The balanced equilibrium reaction will be,

$CaSO_4\rightleftharpoons Ca^{2+}+SO_4^{2-}$

The expression for solubility constant for this reaction will be,

$K_{sp}=(s)\times (s)$

$K_{sp}=(s)^2$

Now put the value of $K_{sp}$ in this expression, we get the solubility of calcium sulfate.

$2.40\times 10^{-5}=(s)^2$

$s=4.89\times 10^{-3}M$

Now we have to calculate the moles of dissolved calcium sulfate in one liter solution.

$\text{Moles of }CaSO_4=\text{Molarity of }CaSO_4\times \text{Volume of }CaSO_4=4.89\times 10^{-3}mole/L\times 1L=4.89\times 10^{-3}\text{ moles}$

Now we have to calculate the moles of calcium sulfate that precipitated.

$\text{Moles of }CaSO_4\text{ precipitated}=\text{Moles of }CaSO_4\text{ present}-\text{Moles of }CaSO_4\text{ dissolved}$

$\text{Moles of }CaSO_4\text{ precipitated}=0.05-4.89\times 10^{-3}=0.045\text{ moles}$

Now we have to calculate the mass of calcium sulfate that precipitated.

$\text{Mass of }CaSO_4\text{ precipitated}=\text{Moles of }CaSO_4\text{ precipitated}\times \text{Molar mass of }CaSO_4$

$\text{Mass of }CaSO_4\text{ precipitated}=0.045moles\times 136g/mole=6.12g$

Therefore, the mass of calcium sulfate precipitate will be, 6.12 grams

5 0

3 years ago

Read 2 more answers

3. How many atoms are in 85 moles H2O?

oksano4ka [1.4K]

Answer:

5.119 *10^25

Explanation:

1 mole = 6.022 * 10^23

$\frac{85 mol H20}{1} =\frac{6.022*10^2^3}{1 mol H20}$

the moles cancel out so you get

85 * (6.022*10^23)

Plug that into the calculator so you get:

5.119 *10^25

8 0

3 years ago

Describe the formation of an ion feom a metal and nonmetal in terms of the octet rule?

strojnjashka [21]

Your answer is QUOTE:

Nonmetals attain stable noble gas configurations by gaining electrons and forming anions with outer electrons in the existing energy level. Metals attain noble gas configurations by losing electrons and forming cations with a complete octet in the next-lowest energy level

6 0

3 years ago