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Alex73 [517]
3 years ago
6

Select the correct answer.

Physics
1 answer:
mart [117]3 years ago
8 0

the production of new machines as a result of processes using science and knowledge

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A graph shows how the temperature of a substance changes as energy is added steadily over time.
OlgaM077 [116]

Answer:

A flat, horizontal line  

Explanation:

A flat, horizontal line indicates a phase change.

The temperature does not increase because the added heat goes into converting one phase into another.

A is wrong. A downward-sloping line indicates that the temperature is decreasing with time.

C is wrong. An upward-sloping line indicates that the temperature is increasing with time.

8 0
3 years ago
Read 2 more answers
A solid sphere of radius R is made of an insulating material. It holds a charge, Q, which is distributed evenly throughout the s
Vinvika [58]

Answer:

The magnitude of Electric Field is E=\dfrac{Qr}{4\pi \epsilon_0 R^3}

Explanation:

Given:

  • Radius of the solid sphere=R
  • Total charge of the sphere=Q

Let consider a Gaussian surface at a distance of r such that  0<r>R in the shape of sphere such that the electric Field due to this E and it is radially outwards.

The charge inside this Gaussian surface volume we have , q_{in}=\dfrac{Qr^3}{R^3}

Now using Gauss Law we have

E\times4\pi r^2=\dfrac{q_{in}}{\epsilon_0}\\E\times4\pi r^2=\dfrac{\dfrac{Qr^3}{R^3}}{\epsilon_0}\\E=\dfrac{Qr}{4\pi \epsilon_0 R^3}

5 0
3 years ago
a fire woman dropped a person onto the safety net. right before the person hit the net he had a velocity of 11.2m/s and 1800j of
Ludmilka [50]

Answer: 28.699

Explanation:

KE=1/2(mv²)

1800=1/2m (125.44)

14.349=2m

m=28.699

5 0
3 years ago
Read 2 more answers
When the mass of the cylinder increased by a factor of 3, from 1.0 kg to 3.0 kg, what happened to the cylinder’s gravitational p
const2013 [10]

Answer: Fourth option. It increased by a factor of 3.

Solution:

m1=1.0 kg

Cylinder's gravitational potential energy: Ep=m*g*h

Ep1=(1.0 kg)*g*h

Ep1=g*h

m2=3.0 kg

Ep2=(3.0 kg)*g*h

Ep2=3*g*h

Replacing g*h by Ep1 in the equation above:

Ep2=3*Ep1

Then, the cylinder's gravitational potential energy increased by a factor of 3.

3 0
4 years ago
Read 2 more answers
A 200 g oscillator in a vacuum chamber has a frequency of 2.0 hz. when air is admitted, the oscillation decreases to 60% of its
ANEK [815]

To solve this given problem, we make use of the formula:

A = Ao e^( − b t / 2 m)

Substituting all the given values into the equation:

A / Ao = e^( − b t / 2 m)

 

When A / Ao = 0.60 and t = 50 s, we find for b:

0.60 = e^( − b t / 2 m)

ln ( 0.60 ) = − b t / 2 m

b = − ( 2 m ) ln ( 0.60 ) / t

b = ( − 2 ) ( .200 ) ln ( 0.60 ) / 50

b = .00409

 

When A / Ao = 0.30, we find for t:

0.30 = e^( − b t / 2 m)

ln ( 0.30 ) = − (0.00409) t / 2 (0.200)

t = − (0.200) ln ( 0.30 ) / 0.00409

t = 118 s

 

Therefore the number of oscillations is:

oscillations = f * t = 2 s^-1 (118 s) = 236

 

Answer: 236 oscillations

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7 0
4 years ago
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