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CaHeK987 [17]
3 years ago
15

1.) Convert 202.1 km to millimeters

Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
3 0

Answer: 2.021 x 10^8 mm or 202,100,000

Explanation: Going from km to mm, you move the decimal place 6 times to the right.

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A chemist requires 5.00 liters of 0.420 M H2SO4 solution. How many grams of H2SO4 should the chemist dissolve in water? 129 gram
natali 33 [55]

Answer:

Approximately 206 grams.

Explanation:

How many moles of sulfuric acid \mathrm{H_2SO_4} are there in this solution?

\text{Number of moles of solute} = \text{Concentration} \times \text{Volume}.

The unit for concentration "\mathrm{M}" is equivalent to mole per liter. In other words, \rm 1\;M = 1\; mol\cdot L^{-1}. For this solution, the concentration of \mathrm{H_2SO_4} is \rm 0.420\;M = 0.420\; mol\cdot L^{-1}.

\begin{aligned}n(\mathrm{H_2SO_4}) &= c(\mathrm{H_2SO_4}) \cdot V\\&= \rm 0.420\;mol\cdot L^{-1}\times 5.00\; L \\&= \rm 2.10\; mol\end{aligned}.

What's the mass of that \rm 2.10\; mol of \mathrm{H_2SO_4}?

Start by finding the molar mass M of \mathrm{H_2SO_4}.

Relative atomic mass data from a modern periodic table:

  • H: 1.008;
  • S: 32.06;
  • O: 15.999.

\displaystyle M(\mathrm{H_2SO_4}) = 2\times \underbrace{1.008}_{\mathrm{H}} + 1\times \underbrace{32.06}_{\mathrm{S}} + 4\times \underbrace{15.999}_{\mathrm{O}} = \rm 98.072\;g\cdot mol^{-1}.

\text{Mass} = \text{Quantity in moles} \times \text{Molar Mass}.

m = n \cdot M = \rm 2.10\; mol \times 98.072\;g\cdot mol^{-1} \approx 206\; g.

In other words, the chemist shall need approximately 206 grams of \mathrm{H_2SO_4} to make this solution. As a side note, keep in mind that the 206 grams of \mathrm{H_2SO_4} also take up considerable amount of space. Therefore it will take less than 5.00 L of water to make the 5.00 L solution.

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