The answer is for part A) 50(1.07(a) )
Answer:
swich the one attached to equation with the one attached to expression
Step-by-step explanation:
an equation need to have an equals sign, an expression doesnt.
Answer:
![8\%](https://tex.z-dn.net/?f=8%5C%25)
Step-by-step explanation:
Since question already gives the number of dollars she will tip, I'm assuming it's asking for percent tipped.
Because the total is $75 and Theresa is tipping $6, she is tipping
of the total. To convert this to a percentage, multiply by 100: ![0.08\implies 0.08\cdot 100=\boxed{8\%}](https://tex.z-dn.net/?f=0.08%5Cimplies%200.08%5Ccdot%20100%3D%5Cboxed%7B8%5C%25%7D)
Answer:
The height of the pile is increasing at the rate of ![\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}](https://tex.z-dn.net/?f=%5Cmathbf%7B%20%5Cdfrac%7B20%7D%7B56.25%20%5Cpi%7D%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%20ft%2Fmin%7D)
Step-by-step explanation:
Given that :
Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min
i.e ![\dfrac{dV}{dt}= 20 \ ft^3/min](https://tex.z-dn.net/?f=%5Cdfrac%7BdV%7D%7Bdt%7D%3D%2020%20%5C%20ft%5E3%2Fmin)
we know that radius r is always twice the diameter d
i.e d = 2r
Given that :
the shape of a cone whose base diameter and height are always equal.
then d = h = 2r
h = 2r
r = h/2
The volume of a cone can be given by the formula:
![V = \dfrac{\pi r^2 h}{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B%5Cpi%20r%5E2%20h%7D%7B3%7D)
![V = \dfrac{\pi (h/2)^2 h}{3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B%5Cpi%20%28h%2F2%29%5E2%20h%7D%7B3%7D)
![V = \dfrac{1}{12} \pi h^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B1%7D%7B12%7D%20%5Cpi%20h%5E3)
![V = \dfrac{ \pi h^3}{12}](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B%20%5Cpi%20h%5E3%7D%7B12%7D)
Taking the differentiation of volume V with respect to time t; we have:
![\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7BdV%7D%7Bdt%20%7D%3D%20%28%5Cdfrac%7Bd%7D%7Bdh%7D%28%5Cdfrac%7B%5Cpi%20h%5E3%7D%7B12%7D%29%29%20%5Ctimes%20%5Cdfrac%7Bdh%7D%7Bdt%7D)
![\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7BdV%7D%7Bdt%20%7D%3D%20%28%5Cdfrac%7B%5Cpi%20h%5E2%7D%7B4%7D%20%29%20%5Ctimes%20%5Cdfrac%7Bdh%7D%7Bdt%7D)
we know that:
![\dfrac{dV}{dt}= 20 \ ft^3/min](https://tex.z-dn.net/?f=%5Cdfrac%7BdV%7D%7Bdt%7D%3D%2020%20%5C%20ft%5E3%2Fmin)
So;we have:
![20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}](https://tex.z-dn.net/?f=20%3D%20%28%5Cdfrac%7B%5Cpi%20%2815%29%5E2%7D%7B4%7D%20%29%20%5Ctimes%20%5Cdfrac%7Bdh%7D%7Bdt%7D)
![20= 56.25 \pi \times \dfrac{dh}{dt}](https://tex.z-dn.net/?f=20%3D%2056.25%20%5Cpi%20%5Ctimes%20%5Cdfrac%7Bdh%7D%7Bdt%7D)
![\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cdfrac%7Bdh%7D%7Bdt%7D%3D%20%5Cdfrac%7B20%7D%7B56.25%20%5Cpi%7D%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%20ft%2Fmin%7D)
The height of the pile is increasing at the rate of ![\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}](https://tex.z-dn.net/?f=%5Cmathbf%7B%20%5Cdfrac%7B20%7D%7B56.25%20%5Cpi%7D%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%20ft%2Fmin%7D)
6900 + 8100 = 15000
15000 divided by 2 = 7500
So your answer is 7500