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Calculate the change in entropy when 10.0 g of CO2 isothermally expands from a volume of 6.15 L to 11.5 L. Assume that the gas b

USPshnik [31]

Answer:

The change in entropy of the carbon dioxide is $1.183\times 10^{-3}$ kilojoules per Kelvin.

Explanation:

By assuming that carbon dioxide behaves ideally, the change in entropy ( $\Delta S$ ), measured in kilojoules per Kelvin, is defined by the following expression:

$\Delta S = m\cdot \bar c_{v}\cdot \ln \frac{T_{f}}{T_{o}}+m\cdot \frac{R_{u}}{M}\cdot \ln \frac{V_{f}}{V_{o}}$ (1)

Where:

$m$ - Mass of the gas, measured in kilograms.

$\bar c_{v}$ - Isochoric specific heat of the gas, measured in kilojoules per kilogram-Kelvin.

$T_{o}$ , $T_{f}$ - Initial and final temperatures of the gas, measured in Kelvin.

$V_{o}$ , $V_{f}$ - Initial and final volumes of the gas, measured in liters.

$R_{u}$ - Ideal gas constant, measured in kilopascal-cubic meter per kilomole-Kelvin.

$M$ - Molar mass, measured in kilograms per kilomole.

If we know that $T_{o} = T_{f}$ , $m = 0.010\,kg$ , $R_{u} = 8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K}$ , $M = 44.010\,\frac{kg}{kmol}$ , $V_{o} = 6.15\,L$ and $V_{f} = 11.5\,L$ , then the change in entropy of the carbon dioxide is:

$\Delta S = \left[\frac{ (0.010\,kg)\cdot \left(8.315\,\frac{kPa\cdot m^{3}}{kmol\cdot K} \right)}{44.010\,\frac{kg}{kmol} } \right]\cdot \ln \left(\frac{11.5\,L}{6.15\,L}\right)$

$\Delta S = 1.183\times 10^{-3}\,\frac{kJ}{K}$

The change in entropy of the carbon dioxide is $1.183\times 10^{-3}$ kilojoules per Kelvin.

4 0

3 years ago

What does state of matter mean

oksano4ka [1.4K]

Answer:

If it is a solid, liquid or gas

Explanation:

5 0

3 years ago

the hcp ordered 0.2 mg of methylergonovine, and the vial contains 0.8 mg/ml. how many ml of methylergonovine should the nurse dr

iogann1982 [59]

The volume (in mL) of methylergonovine the nurse should draw up in the syringeis is 0.25 mL

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

With the concept of density, we can obtain the volume of methylergonovine. Details below

<h3>How to determine the volume </h3>

The following data were obtained from the question:

Mass = 0.2 mg
Density = 0.8 mg/mL
Volume =?

Density = mass / volume

Cross multiply

Density × volume = mass

Divide both sides by density

Volume = mass / density

Volume = 0.2 / 0.8

Volume = 0.25 mL

Learn more about density:

brainly.com/question/952755

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6 0

1 year ago

The pale yellow liquid bromine pentafluoride reacts violently with water to give a mixture of bromic acid and hydrofluoric acid

topjm [15]

Answer:

The concentration of bromic acid (HBrO₃) is 0.069 moles/L

the concentration of hydrofluoric acid (HF) is 0.345 moles/L

Explanation:

(a) The balanced chemical equation for the reaction is

BrF₅ + 3H₂O → HBrO₃ + 5HF

The chemical equation is balanced

(b) To determine the concentration of each acids,

First, we will determine the different volume of the acids yielded

The solution volume is 783 mL = 0.783 L

From the balanced chemical equation,

1 mole of BrF₅ produces 1 mole of HBrO₃

Likewise, 1 mole of BrF₅ will produce 5 moles of HF

From the question,

5.40×10⁻² moles of bromine pentafluoride (BrF₅) reacted;

Hence, 5.40×10⁻² moles of HBrO₃ will be produced

and 5 × 5.40×10⁻² moles of HF will be produced.

Number of moles of HBrO₃ produced = 5.40×10⁻² moles

and Number of moles of HF produced = 2.7 × 10⁻¹ moles

From the formula,

Number of moles (n) = Concentration (C) × Volume (V)

Then,

Concentration (C) = Number of moles (n) / Volume (V)

For bromic acid (HBrO₃)

n = 5.40×10⁻² moles

Volume = 0.783L

Hence,

C = 5.40×10⁻² moles / 0.783L

C = 0.069 moles/L

This is the concentration of bromic acid (HBrO₃)

For hydrofluoric acid (HF)

n = 2.7 × 10⁻¹ moles

V = 0.783L

Hence,

C = 2.7 × 10⁻¹ moles / 0.783L

C = 0.345 moles/L

This is the concentration of hydrofluoric acid (HF)

3 0

3 years ago

55 points say 5 "55" times

Aneli [31]

Answer:

5555555555555555555555555555555555555555555555555555555

3 0

4 years ago

Read 2 more answers