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Zepler [3.9K]
2 years ago
14

Hello! Can you help you can get more points! Click on the photo for more view etc.

Mathematics
1 answer:
Murrr4er [49]2 years ago
4 0

Answer:

22,950

Step-by-step explanation:

subtract 51,550 and 28,600. 0 - 0 = 0 then 5-0=5 5-6 you can not do so you barrow from the 1. 1 becomes 0 and 5 becomes 15. 15-6=9. 0-8 you can not do so you need to borrow from the 5. 5 becomes 4 and 0 becomes 10. 10-8=2. Finally, 4-2=2. Put is all together and you have 22,950.

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A train leaves thorn junction at 1:25 p.m. and arrives in niles at 3:05 p.m. the train makes two stops along the route for a tot
KonstantinChe [14]

The time taken by the first and the second train is 1 hour 40 minutes and 1 hour 25 minutes. Then the time when the second train at Niles junction is 5:55 p.m.

<h3>What is speed?</h3>

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

\rm Speed = \dfrac{Distance}{Time}

A train leaves Thorn junction at 1:25 p.m. and arrives in Niles at 3:05 p.m. the train makes two stops along the route for a total of 15 minutes.

A second train leaves Thorn junction at 4:30 p.m. and heads to Niles.

This train does not make any stops.

Let the speed of both trains be equal.

Then the time taken by the first train will be

t₁ = 3:05 p.m. - 1:25 p.m.

t₁ = 1 hour 40 minutes

Then the time taken by the second train will be

t₂ = 1:40 - 00:15

t₂ = 1:25 = 1 hour 25 minutes

The time when the second train is at Niles junction will be

→ 4:30 p.m. + 1:25

→ 5:55 p.m.

More about the speed link is given below.

brainly.com/question/7359669

#SPJ1

3 0
2 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

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x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
2 years ago
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Black_prince [1.1K]

Answer:

The last one

Step-by-step explanation:

f(2) = 4x-5 = 3

f(-4) = 4x - 5 = -21

F(2) has a greater value than f(-4)

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2 years ago
What is the distance between (5, -1) and (5,-4)?
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Mathspapa.com ok find it there
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17.3, 18.2, 19.1, 20
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