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kari74 [83]
3 years ago
13

How does light reflect from the surface of carbon, copper wire, and the silicon lump? Does it appear metallic or nonmetallic (is

it shiny or dull)?
Physics
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

When a light wave hits a metallic surface, the electrons on the surface are pushed and ... in a process called "total internal reflection", making that surface look shiny too.

Explanation:

metallic shiny nonmetallic dull:)

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What is the the acceleration of a proton that is 4.0 cm from the center of the bead? input positive value if the acceleration is
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Missing detail in the text:
"<span>A small glass bead has been charged to + 25 nC "

Solution
The force exerted on a charge q by an electric field E is given by
</span>F=qE
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span>E=k_e  \frac{Q}{r^2}
with k_e = 8.99\cdot 10^9 Nm^2/C^2, Q=+25 nC=25 \cdot 10^{-9}C is the charge on the bead. We want to calculate the field at r=4.0 cm=0.04 m:
E=(8.99\cdot 10^9) \frac{25\cdot 10^{-9}}{(0.04)^2}=1.4\cdot 10^5 V/m
The proton has a charge of q=1.6\cdot 10^{-19}C, therefore the force exerted on it is
F=qE=1.6\cdot 10^{-19}C \cdot 1.4\cdot 10^5 V/m=2.25\cdot 10^{-14} N

And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass, m=1.67\cdot 10^{-27} kg, we have
F=ma
a= \frac{F}{m}= \frac{2.25\cdot 10^{-14} N}{1.67\cdot 10^{-27} kg}=1.35 \cdot 10^{13} m/s^2

The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
a=-1.35 \cdot 10^{13} m/s^2
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