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eimsori [14]
3 years ago
10

I don’t understand how to solve this. Please explain the steps. Thanks.

Mathematics
2 answers:
statuscvo [17]3 years ago
3 0

Answer:

D

Step-by-step explanation:

When you are raising something to a fractional power, you are raising it to the power of the numerator and finding the root denoted by the denominator. The explanation above is kinda confusing, so here is an example:

x^(3/5)

This would be written as:

\sqrt[5]{x^3}

Now for the actual problem. Since the numerator is 4, we start by raising x to the 4th power, x^4.

Because the denominator is 5, we find the 5th root:

\sqrt[5]{x^4}

This matches none of the answers shown, so the answer is none of the above or D.

trapecia [35]3 years ago
3 0

Answer:

D

Step-by-step explanation:

The answer would be 5 square root x^4

See Image Below:)

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Solve the equation, justify<br> each step with an algebraic<br> property<br> -(x - 6) = 4
lesantik [10]

Answer:

x=2

Step-by-step explanation:

Step 1_  −(x−6)=4

              −x+6=4(Distribute)

               −x+6=4

Step 2_       −x+6−6=4−6

                   −x=−2

Step 3_       −x    equals   -2

                    −1                   -1

x=2

Hope this helps :)

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3 years ago
The value of y varies inversely with x. what is the value of k when y=12.7 and x=8?
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Step-by-step explanation:

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7 0
3 years ago
In ΔUVW, the measure of ∠W=90°, WV = 39, UW = 80, and VU = 89. What ratio represents the cosine of ∠U?
kumpel [21]

Answer:

cos ∅ = 80/89

Step-by-step explanation:

As required from the question the picture below represent a triangle UVW . The angle W = 90°. The sides WV = 39 , VU = 89 and UW = 80. The triangle forms a right angle triangle .

Such triangle one can establish trigonometric relationship using the SOHCAHTOA principle.

The question requested us to find the ratio that represent the cosine of  ∠U.

The ∠U is represented as ∅ .

Therefore,

cos ∅ = adjacent/hypotenuse

adjacent = 80. The adjacent side is the non hypotenuse side that is next to the given angle.

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cos ∅ = adjacent/hypotenuse

cos ∅ = 80/89

5 0
3 years ago
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