The a answer to the statement is between B and D
Answer:
N₂H₆
Explanation:
A 1.000 g sample of nitrogen combined with a 0.0720 g sample of hydrogen to form N₂H₂ .
1.000 g of nitrogen combines with 0.2160 g of hydrogen in the next compound .
In this compound the component of nitrogen remains the same but the component of hydrogen becomes .2160 / .0720 = 3 times .
Hence component of hydrogen in the new compound will change from
H2 to H6 .
Hence the chemical formula of new compound will be
N₂H₆ .
It can form dipole-dipole interactions but that’s all
The answer is 60.3% magnesium, 39.7% oxygen.
Solution:
The chemical equation for the reaction is 2 Mg + O2 → 2 MgO.
Since magnesium reacts completely with oxygen, it is the limiting reactant in the reaction. Hence, we can use the number of moles of magnesium to get the mass of MgO produced:
moles of magnesium = 14.7g / 24.305g mol-1
= 0.6048 mol
mass of MgO = 0.6048mol Mg(2 mol MgO/2mol Mg)(40.3044g MgO/1 mol MgO)
= 24.376g MgO
We can now solve for the percentage of magnesium:
% Mg = (14.7g Mg / 24.376g MgO)*100% = 60.3%
We also use the number of moles of magnesium to get the mass of oxygen consumed in the reaction:
mass of O2 = 0.6048 mol Mg (1mol O2 / 2mol Mg) (31.998g / 1mol O2)
= 9.676g
The percentage of oxygen is therefore
% O2 = (9.676g O2 / 24.376g MgO)*100%
= 39.7%
Notice that we can just subtract the magnesium's percentage from 100% to get
% O2 = 100% - 60.3% = 39.7%
Answer:
Option A
Explanation:
Leguminous plants like pulses etc. have root nodules comprising of rhizobacterium which live in a symbiotic relationship with the roots of the plant and in turn fix the nitrogen in the soil in the roots of the leguminous plants.
Hence, option A is correct
