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Elden [556K]
3 years ago
6

Should you choose to throw a rubber ball, which will bounce off the pin, or a beanbag, which will strike the pin and not bounce

Physics
1 answer:
FrozenT [24]3 years ago
3 0

Answer:

Hey

(I think this is the weirdest question I have ever answered)

If you are trying to catch it then use the beanbag. But if you are trying to not catch it use the rubber ball instead.

Hope it helped

Spiky Bob your answerer

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Init. A
Gekata [30.6K]

Answer:

v = 1/3 m / s = 0.333 m / s

in the direction of the truck

Explanation:

The average speed is defined by the variation of the position between the time spent

           v = Δx / Δt

since the position is a vector we must add using vectors, we will assume that the displacement to the right is positive, the total displacement is

           Δx = 20 - 15 +20

           Δx = 25 m

therefore we calculate

         v = 25/75

         v = 1/3 m / s = 0.333 m / s

in the direction of the truck

7 0
3 years ago
If you wanted to get yellow light , what part of the of the spectrum would the color filter have to absorb ?
densk [106]
The filter would need to absorb every color EXCEPT yellow. It would have to absorb red orange green blue and violet.
4 0
3 years ago
A 37 kg object has an applied force of 85N [R] acting on it. The coefficient of
Sliva [168]

Answer:

Explanation:

This is quite tricky! You need to do 2 different equations to solve all the parts of this problem. First is finding the acceleration in one dimension, which has an equation of

F - f = ma

where F is the applied Friction,

f is the frictional force acting against F,

m is the mass of the object, and

a is the acceleration of the object (NOT the velocity!)

This is Newton's Second Law expanded on a bit. The sum of the forces working on an object is equal to the object's mass times its acceleration. We have F, but we need f which is found in the equation

f = μF_n which is the coefficient of kinetic friction times the weight of the object. Weight is found in the equation

w = mg where m is mass and g is the pull of gravity. Let's start there and work backwards:

w = 37(9.8) to 2 sig figs so

w = 360N. Now fill that in to find f:

f = (.17)(360) to 2 sig figs so

f = 61. Now for the final answer in the original equation way back up at the top:

85 - 61 = 37a and do the subtraction on the left side first:

24 = 37a and then we divide to 2 sig figs to get

a = .65 m/s/s

Since we are moving in a straight line (as opposed to on an angle) the displacement is found in

d = rt which simply says that the distance an object moves is equal to its rate times the time. Therefore,

d = 2.2(3.4) to 2 sig figs so

d = 7.5 m

6 0
3 years ago
A pulley with a radius of 3.0 cm and a rotational inertia of 4.5 x 10^-3 kg∙m2 is suspended from the ceiling. A rope passes over
solmaris [256]

Answer:

maximum kinetic energy is for Pulley

e) The pulley

Explanation:

Let 4 kg block is moving downwards with speed "v" so we can say that 2 kg block will move upwards with same speed "v"

Now we know that pulling is in pure rotational motion

so we will have

\omega = \frac{v}{R}

\omega = \frac{v}{0.03}

now kinetic energy of each is given as

For 4 kg block

K_1 = \frac{1}{2}(4)(v^2) = 2v^2

for 2 kg block

K_2 = \frac{1}{2}(2)(v^2) = v^2

For pulley

K_3 = \frac{1}{2}I\omega^2

K_3 = \frac{1}{2}(4.5\times 10^{-3})\frac{(v^2)}{0.03^2}

K_3 = 2.5 v^2

So maximum kinetic energy is for Pulley

3 0
3 years ago
A man-made satellite orbits the earth in a circular orbit that has a radius of 32000 km. The mass of the Earth is 5.97e 24 kg. W
Gwar [14]

Answer:

= 3521m/s

The tangential speed is approximately 3500 m/s.

Explanation:

F = m * v² ÷ r

Fg = (G * M * m) ÷ r²

(m v²) / r = (G * M * m) / r²

v² = (G * M) / r

v = √( G * M ÷ r)

G * M = 6.67 * 10⁻¹¹ * 5.97 * 10²⁴ = 3.98199 * 10¹⁴

r = 32000km = 32 * 10⁶ meters  

G * M / r = 3.98199 * 10¹⁴ ÷ 32 * 10⁶

v = √1.24 * 10⁷  

v = 3521.36m/s

The tangential speed is approximately 3500 m/s.

8 0
4 years ago
Read 2 more answers
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