Answer:
The motion of the block is downwards with acceleration 1.7 m/s^2.
Explanation:
First, we will calculate the acceleration using the kinematics equations. We will denote the direction along the incline as x-direction.
Newton’s Second Law can be used to find the net force applied on the block in the -x-direction.
Now, let’s investigate the free-body diagram of the block.
Along the x-direction, there are two forces: The x-component of the block’s weight and the kinetic friction force. Therefore,
As for the static friction, we will consider the angle 31.8, but just before the block starts the move.
The coefficient of static friction is 0.222
Explanation:
In order for the car to remain in circular motion, the frictional force must be able to provide the necessary centripetal force. Therefore, the car will start skidding when the two forces are equal:
where the term on the left is the frictional force, while the term on the right is the centripetal force, and where
is the coefficient of static friction
m is the mass of the car
g is the acceleration of gravity
v is the speed of the car
r is the radius of the track
In this problem, we have:
r = 564 m
v = 35 m/s
And re-arranging the equation for , we can find the coefficient of static friction:
Learn more about friction:
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We have: a = v/t
Here, t = 2 s [ Given ]
a = 9.8 m/s² [constant value for earth system ]
Substitute their values into the expression:
9.8 = v/2
v = 9.8 × 2
v = 19.6 m/s
In short, Your Answer would be Option B
Hope this helps!
<h2>The emf produced is 7.2 V</h2>
Explanation:
When coil is placed in the magnetic field , the flux attached with it can be found by the relation . Flux Ф = the dot product of magnetic field and area of coil .
Thus Ф = B A cosθ
here B is magnetic field strength and A is the area of coil .
The angle θ is the angle between coil and field direction .
When coil rotates , the angle varies . By which the flux varies . The emf is produced in coil due to variation of flux . The relation for this is
The emf produced ξ = - 
= B A sinθ 
Now in the given problem
5 = 0.38 x A x I
Now if the magnetic field is 0.55 T and all the other terms are same , the emf produced
ξ = 0.55 x A x Ii
dividing II by I , we have
= 
= 1.45
or ξ = 7.2 V
