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3 years ago

Which set of ordered pairs in the form (x,y) does not represent a function of x?

2 answers:

7 0

If we are going to analyze the sets of ordered pairs listed above, we can easily spot which set of ordered pairs in the form of (x,y) that does not represent a function of x. If the first coordinates of each ordered pair are all different, then it is a function; but if the first coordinates have repeated numbers, then it is not. Therefore, the answer would be option C. Notice that 3 is repeated. Hope this helps.

kifflom [539]3 years ago

5 0

Answer:

Option C

Step-by-step explanation:

A function is a relation that does not contain two pairs with same first component.

Option A

{(-1,2),(3,-2),(0,1),(5,2)} is a function, since there are no two pairs with the same first component.

option B

{(-1,2),(3,2),(-2,2),(0,2)} is a function, since there are no two pairs with the same first component.

option C

{(-1,2),(3,-2),(0,1),(3,5)} is not a function, since there are two pairs with the same first component i.e, 3

OptionD

{(-1,2),(2,3),(3,-2),(-2,0)} is a function, since there are no two pairs with the same first component.

So, {(-1,2),(3,-2),(0,1),(3,5)} is the required answer.

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You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

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3 years ago

PLZ HELP Factor: x^9 - 9x + 20

Blizzard [7]

Answer:

The problem can't be factor

Step-by-step explanation:

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4 years ago

Read 2 more answers

A line passes through (6, 3), (8, 4), and (n, -2). Find the value of n.

timurjin [86]

Answer:

n = -4

Step-by-step explanation:

Notice how in the previous examples they all divide by 2? It is the same case here. So now the question is... "what" divided by "2" is "-2".

Let me show you:

n ÷ 2 = -2

if you know your integer math, you should know that...

-4 ÷2 = -2 (this is the correct equation)

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1 year ago

Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa

Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation

n=580 represent the random sample taken

X represent the seafood sold in the country that is mislabeled or misidentified by the people

$\hat p=0.25$ estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

$\alpha=0.01$ represent the significance level (no given, but is assumed)

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204$

$0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296$

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).

Part c

A government spokesperson claimed that the sample size was too small, relative to the billions of pieces of seafood sold each year, to generalize. Is this criticism valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

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4 years ago

What is the rate of change of the function described in the

Debora [2.8K]

5 because if you multiply the previous value by 5, you get the next answer

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4 years ago