Find the number of moles of sodium you have:
<span>n = m/M where m is your 20g of sodium and M is 22.99 g/mol. </span>
<span>Look at the stoichiometry of the equation - it's 2:2 when you are producing NaOH. So if you took 1 mole of Na, it'd produce 1 mole of NaOH (as the ratio is equal). </span>
<span>That means that your moles of sodium is equal to the moles of NaOH produced. Use the molar mass of NaOH - which is 39.998 g/mol along with your calculated number of moles to get the mass (the formula rearranges to m = nM). </span>
<span>This figure is the theoretical yield - what you would get if every last mole of sodium was converted into NaOH. </span>
<span>What you get in practice is the experminetal yield, and the percentage yield is the experimental yield divided by the theoretical yield - and then multiplied by 100%.</span>
Answer:
True.
Explanation:
Now i'm not 100% sure if this is the answer but i believe depending on what you are making/mixing would depend on the answer, this answer probably won't be the same in context of slim making but it could mean true for other things, so without knowing much i would guess True.
Answer:
Gibbs free energy equation
Explanation:
An example of an aqueous solution of a strong base is NaOH (sodium hydroxide) in water. The NaOH dissociates completely in water into Na+ and OH- ions. An example of an aqueous solution of a weak base is NH3 (ammonia) in water. Here, the NH3 does not completely dissociate because it is a weak base.
