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Umnica [9.8K]
3 years ago
11

How many elements are found in the following chemical equation? K + Cl → KCl

Chemistry
2 answers:
KengaRu [80]3 years ago
8 0
There are 2 elements in the equation that form a product
Over [174]3 years ago
4 0

Answer:

2

Explanation:

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For the equation 3Cu + 8HNO3 → 3Cu(NO3)2 + 2NO + 4H2O, how many units of NO3 are represented on the products side?
topjm [15]

Answer:

6

Explanation:

3 * 2 =6

5 0
2 years ago
Determine the concentration of H+ ions in an aqueous solution where [OH-] =2.25 × 10^-4 M. I have 29 minutes I beg u guys pls hu
mixas84 [53]

but where Is the volume in order for us to determine the concentration. since we have moles in H+ ions

then you can say

concentration = M*1000/V

6 0
3 years ago
​If a bag of peas weighs 454 grams, how many peas would be in the bag?
OverLord2011 [107]

​In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

The average pea weighs between 0.1 and 0.36 grams.

If we take the lower value (0.1 g/pea), the number of peas in 454 g is:

454 g \times \frac{1pea}{0.1 g} = 4540pea

If we take the higher value (0.36 g/pea), the number of peas in 454 g is:

454 g \times \frac{1pea}{0.36 g} \approx  1261pea

​In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

You can learn more about conversion factors here: brainly.com/question/1844638

6 0
2 years ago
Which best describe the tyndall effect
Svet_ta [14]

The answer would be A

6 0
3 years ago
0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

4 0
3 years ago
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