Answer:
Q ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
Explanation:
Three heat transitions need be considered. Cooling the steam to 100°C, condensing the steam to water and cooling the water from 100°C to 87°C.
Total Heat exchange (Q) = ∑ heat transitions
Q = (m·c·ΔT)steam + (m·ΔH)condensation + (m·c·ΔT)water cooling
= (50g x 0.48j/g·°C x 14°C) + (50g x 2259j/g) + (50g x 4.184j/g·°C)
= 24j + 112,950j + 209.2j
= 113,183.2j ≈ 1 x 10⁵ joules (1 sig. fig. based on 50g sample given)
A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.
Energy is a property that is transferred to a physical system, recognizable in the performance of work and in the form of heat and light.
A small sample of methane undergoes combustion. As the hot gas mixture expands, it releases energy (E).
- It releases 120.0 kJ of heat. By convention, when heat is released, we assign it a negative sign. Thus, q = -120.0 kJ.
- It does 830.0 kJ of work. By convention, when the system does work on the surroundings, we assign it a negative sign. Thus, w = -830.0 kJ.
The change in the energy is the sum of the heat released and the work done.
ΔE = q + w = -120.0 kJ + (-830.0 kJ) = -950.0 kJ
A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.
Learn more about energy here: brainly.com/question/13881533
Answer:
B. Lower
Explanation:
Remember that the pH is calculated as
-log (H30 +)
That is, at a higher concentration of H30 +, with the -log, the pH value decreases and vice versa.
With a concentration 1e-5, it yields a pH of 5.00 and with 1e-2 a value of 2.00
Answer:
1st page, number a-ENergy is added or absorbed
I cant see the answers on the 2nd page
Explanation:
