Physical properties of metal include shiny, ductile, opaque, malleable and good conduction of heat and electricity
Buckyball or buckminster fullerene is the third allotrope of carbon. It contains 60 carbons which are arranged in the five and six membered rings. Buckyball is the cluster of carbon atoms which are arranged in spherical shape and it forms a hollow cage.
The physical properties are:
Buckyball is made up of huge number of molecules but giant covalent bond is not exist.
The forces between the individual buckyballs are weak intermolecular forces.
The substances which are made up of buckyballs has low melting point in comparison to other allotropes of carbon as low energy is required to overcome theses intermolecular forces.
The substances which are made up of buckyballs is slippery in nature.
The solutions of buckminster fullerene are deep purple in color and upon evaporation brown residue is obtained.
Buckyball is soft in comparison to graphite and when it is compressed to less than 70 percent of its volume then, it converts into superhard form of diamond.
Answer:
Explanation:
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In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:
Whereas the three aqueous salts are ionized in order to write the following complete ionic equation:
In such a way, since the cesium and nitrate ions are the spectator ions because of the aforementioned, the net ionic equation turns out:
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The concentration of mixed solution = 0.5 M
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Further explanation
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Given
0.5 M HCl
0.5 M Ca(OH)₂
Required
The concentration
Solution
Molarity from 2 solutions :
Vm Mm = V₁. M₁ + V₂. M₂
m = mixed solution
V = volume
M = molarity
V = mixed volume
1 = solution 1
2 = solution 2
Vm = V₁+V₂
Equal volumes⇒V₁=V₂, and Vm = 2V, then equation becomes :
2V.Mm = V(M₁+M₂)
2V.Mm = V(0.5+0.5)
Mm=0.5 M
